Marram spent 3/4 of her allowance at the mall. Of the money spent at the mall1/3 was spent on new earrings. What part of her all
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Answer:
492
Step-by-step explanation:
As per the given data of the question:
Total number of students = 2504
Number of students in Java (J) = 1876
Number of students in Linux (L) = 999
Number of students in C = 345
J∩L = 876
L∩C = 231
C∩J = 290
L∩J∩C = 189
Now according to Venn-diagram as drawn below:
Number of students haven taken courses in Java and Linux both only
= J∩L - L∩J∩C
= 876 - 189
= 687
Number of students haven taken courses in Java and C both only
= C∩J - L∩J∩C
= 290 - 189
= 101
Number of students haven taken courses in C and Linux both only
= L∩C - L∩J∩C
= 231 - 189
= 42
Therefore,
Number of students only in Java = 1876 - 687 - 189 - 101 = 899
Number of students only in Linux = 999 - 687 - 189 - 42 = 81
Number of students only in C = 345 - 42 - 189 - 101 = 13
So,
Number of students who have not taken a course in any of these three subjects
= 2504 - 899 - 81 - 13 - 687 - 189 -101 - 42
= 492
Hence, the students who have not taken a course in any of these three subjects = 492.
Let's call L the width of the rectangle and W its width. The area of the rectangle is the product between the length and the width, and we are also told that the area is 300 square meters, so we can write
Moreover, we know that the length is 5 meters longer than the width:
We have a system of 2 equations in 2 unknown variables, L and W. If we substitute the second equation into the first one, we get
which has two solutions: W=-20 and W=15. We can discard the negative solution since it does not have physical meaning, and now we can substitute the value of W into the second equation to find L:
<span>Therefore, the rectangle has width 15 meters and length 20 meters.</span>
Moreover, we know that the length is 5 meters longer than the width:
We have a system of 2 equations in 2 unknown variables, L and W. If we substitute the second equation into the first one, we get
which has two solutions: W=-20 and W=15. We can discard the negative solution since it does not have physical meaning, and now we can substitute the value of W into the second equation to find L:
<span>Therefore, the rectangle has width 15 meters and length 20 meters.</span>