For this case we have the following equation:

We must find the value of "x":
We apply cube root on both sides of the equation to eliminate the exponent:
![x = \sqrt [3] {375}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B375%7D)
We can write 375 as 
So:
![x = \sqrt [3] {5 ^ 3 * 3}\\x = 5 \sqrt [3] {3}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B5%20%5E%203%20%2A%203%7D%5C%5Cx%20%3D%205%20%5Csqrt%20%5B3%5D%20%7B3%7D)
Then, the correct options are:
![x = \sqrt [3] {375}\\x = 5 \sqrt [3] {3}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B375%7D%5C%5Cx%20%3D%205%20%5Csqrt%20%5B3%5D%20%7B3%7D)
Answer:
Option A and B
the distance between 16 and -25 is 41
Answer:
From the frequency table, let's calculate the row total.
Row total for phone call = 19 + 9 = 28
Row total for no phone call = 8 +6 = 14
To calculate their respective row relative frequencies, let's use:
Row relative freq =
Now, the two-way frequency table will be computed as:
For phone call:
Desirable behavior =
≈0.69
Undesirable behaviour =
≈0.32
No phone call:
Desirable behaviour =
≈ 0.57
Undesirable behaviour =
≈ 0.43
The complete two-way table is attached.
Answer:
Fixed cost $14 -350 messages
variable $ 0.25 each message<u> i think</u>
Step-by-step explanation:
Answer:
The final result is: n = 7/10 or n = 0.7.
I think