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Naddika [18.5K]
3 years ago
8

Describe a transformation that could be used to show that alternate interior angles are congruent.

Mathematics
1 answer:
Aliun [14]3 years ago
7 0

Answer:

Step-by-step explanation:

From the picture attached,

Let 'l' be the original line having one angle ∠BAC.

If the original line 'l' is shifted or translated to line 'm', angle BAC will replace the angle BDE.

Since, measure of angles are preserved in the translation,

m∠BDE = m∠BAC [corresponding angles]

Since, ∠BDE ≅ ∠MDA [Vertical angles]

Therefore, m∠MDA = m∠BAC

Hence, alternate interior angles (∠MDA) and (∠BAC) will be congruent when line 'l' is translated to line 'm'.

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a) Michiko needs to buy 18 tins of paint.

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Surface area of cuboid = 2lw + 2lh + 2hw

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Width (w) = 1.2 m

Height (h) = 0.6 m

SF = 2(2.4 × 1.2) + 2(2.4 × 0.6) + 2(0.6 × 1.2)

   = 5.76 + 2.88 + 1.44

   = 10.08 meter²

Paint coverage is 4.5 meter² per liter.

Total paint used in one coat =

                                              = 2.24 liters

Paint used in double coats = 2.24 × 2 = 4.48 liters

a) Size of one tin paint = 250 ml

1 liters = 1000 ml

4.48 liters = 4.48 × 1000 = 4480 ml

Number of tins needed by Michiko =

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b) Cost of one tin of metal paint = $8.49

∴ cost of 18 tins of paint = $152.82

a) Michiko needs to buy 18 tins of paint.

b) cost of paint would be $152.82

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2 years ago
Find the 10th term of the geometric sequence whose common ratio is 2/3 and whose first term is 3.
Sergeu [11.5K]

Answer:

\frac{512}{6561}

Step-by-step explanation:

1) if according to the condition a₁=3 and r=2/3, then a₁₀ can be calculated as:

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2) according  to the rule above:

a₁₀=3*(2/3)⁹=512*3/(6561*3)=512/6561.

5 0
2 years ago
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