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3 years ago

14

1st what does this situation refers to?

1 answer:

levacccp [35]3 years ago

5 0

Can u go closer I can’t see

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Find the surface area of the prism

Tema [17]

<h2>find the total surface area of a prism, you need to calculate the area of two polygonal bases, i.e., the top face and bottom face. And then calculate the area of lateral faces connecting the bases. Add up the area of the two bases and the area of the lateral faces to get the total surface area of a prism.</h2>

<h2>i HOPE IT'S HELP </h2>

3 0

2 years ago

A particular fruit's weights are normally distributed, with a mean of 476 grams and a standard deviation of 36 grams. The heavie

4vir4ik [10]

Answer:

Step-by-step explanation:

Given that:

mean (μ) = 476 grams, standard deviation (σ) = 36 grams. P(z) = 19%

The z score shows by how many standard deviation the raw score is above or below the mean. It is given by the equation:

$z=\frac{x-\mu}{\sigma}$

Since the 19% weigh more, therefore 81% (100% - 19%) weigh less.

From the normal distribution table, the z score that corresponds to a probability of 81%(0.81) = 0.87

We substitute z = 0.88 in the z score equation to find the raw score. Therefore:

$z=\frac{x-\mu}{\sigma}\\0.87=\frac{x-476}{36}\\ x-476=31.32\\x=31.32+476\\x=507.32\\$

x ≅ 507 grams

Therefore 19% of fruits weigh more than 507 grams

7 0

3 years ago

i need to find the area of a rectangle using the formula A=b*h the height is 810 cm the base is 10 meters...i know i need to con

leva [86]

Answer:

81000 $cm^{2}$ or 8.1 $m^{2}$

Step-by-step explanation:

1m = 100cm

10m = 1000cm

a= b*h

a= 1000cm * 810cm

= 810000 $cm^{2}$

1 $m^{2}$ = 10000 $cm^{2}$

810000 $cm^{2}$ = 8.1 $m^{2}$

7 0

3 years ago

The vertices of quadrilateral MNPQ are M(−3,−2),N(−1,4),P(2,4), and Q(4,−2). Translate quadrilateral MNPQ using the vector ⟨3,−4

muminat

Answer:

see explanation

Step-by-step explanation:

A translation using the vector < 3, - 4 > , means

Add 3 to the x- coordinate and subtract 4 from the y- coordinate, so

M (- 3, - 2 ) → M' (- 3 + 3, - 2 - 4 ) → M' (0, - 6 )

N (- 1, 4 ) → N' (- 1 + 3, 4 - 4 ) → N' (2, 0 )

P (2, 4 ) → P' (2 + 3, 4 - 4 ) → P' (5, 0 )

Q (4, - 2 ) → Q' (4 + 3, - 2 - 4 ) → (7, - 6 )

4 0

2 years ago

The sum of three numbers is 104. The first number is 10 less than the second. The third number is 4 times the second. What are t

Shalnov [3]

Answer:

The numbers are 9, 19 and 76.

Step-by-step explanation:

Let's take the second number and make it a variable, like x. Now let's find all the other numbers in terms of x.

The first number in terms of x:

$x - 10$

The second number in terms of x:

$4x$

If we add them all up, these 3 numbers in terms of x must be equal to 104, so:

$x + (x - 10) + (4x) = 104 \\ x + x - 10 + 4x = 104 \\ 6x - 10 = 104 \\ 6x = 114 \\ x = 19$

Now that we know the second number, we can find the other numbers since we already figured out their values in terms of x:

$19 - 10 = 9$

$4 \times 19 = 76$

The first number is 9, second number 19 and the third number 76.

6 0

3 years ago