Answer:
sorry no idea hhcchuucghhf
The answer is <span>B. 25 adults; 15 children.</span>
Answer:
The distance between A and A' is:
![distance=\sqrt{20}](https://tex.z-dn.net/?f=distance%3D%5Csqrt%7B20%7D)
Step-by-step explanation:
Notice that point A' after the given translation becomes: (-2+4, 3+2) = (2, 5),
So one can calculate the distance between A (-2, 3) and A' (2, 5) using the distance formula:
![distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\distance=\sqrt{(2-(-2))^2+(5-3)^2} \\distance=\sqrt{(4))^2+(2)^2} \\distance=\sqrt{(16+4} \\distance=\sqrt{20}](https://tex.z-dn.net/?f=distance%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D%5C%5Cdistance%3D%5Csqrt%7B%282-%28-2%29%29%5E2%2B%285-3%29%5E2%7D%20%5C%5Cdistance%3D%5Csqrt%7B%284%29%29%5E2%2B%282%29%5E2%7D%20%5C%5Cdistance%3D%5Csqrt%7B%2816%2B4%7D%20%5C%5Cdistance%3D%5Csqrt%7B20%7D)
(5,12,13) is a right triangle and can be constructed.
All the others do not satisfy the triangle inequality, i.e. the sum of two short sides must exceed the long side in order for the triangle to be constructed.
Examples:
2+11<15, so no
3+7<11, so no
4+8<15, so no
but 5+12>13 so yes, it can be constructed.
Your Answer Is...
94 R 114.
Glad I Could Help, And Good Luck!
My Brainly Name: AnonymousGiantsFan