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gogolik [260]
1 year ago
8

I will mark brainlyist

Mathematics
1 answer:
leva [86]1 year ago
6 0

Using it's definitions, the five-number summary and the interquartile range for the data-set is given as follows:

  • Minimum: 6
  • Lower quartile: 8
  • Median: 21.
  • Upper quartile: 27
  • Maximum: 35
  • Interquartile range: 19

<h3>What are the median and the quartiles of a data-set? How to find the interquartile range using it?</h3>

  • The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
  • The first quartile is the median of the first half of the data-set.
  • The third quartile is the median of the second half of the data-set.
  • The interquartile range is the difference of the third quartile and the first quartile.

This data-set has 12 elements, which is an even number, hence the median is the mean of the 6th and 7th elements, as follows:

Me = (19 + 23)/2 = 21.

The minimum is the lowest value in the data-set, which is of 6, while the maximum is of 35, which is the largest value in the data-set.

The first quartile is the median of the first half, composed by 6, 7, 8, 8, 16, which is the third element of 8.

The third quartile is the median of the second half, composed by 23, 24, 26, 27, 34, 35, which is of 27. Hence the interquartile range is of 27 - 8 = 19.

More can be learned about the five-number summary and the interquartile range at brainly.com/question/3876456

#SPJ1

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Step 2:

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Standard\text{ Deviation}=\sqrt{\sum_{i\mathop{=}0}^3(x_i-\mu)^2P_(x_i)}=(0-2)^2(0.25)+(1-2)^2(0.05)+(2-2)^2(0.15)+(3-2)^2(0.55)=4(0.25)+1(0.05)+0(0.15)+1(0.55)=1+0.05+0+0.55=1.60

Thus, the standard deviation is 1.60

Answer:

1.60

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