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2 years ago

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Mathematics

1 answer:

Ksenya-84 [330]2 years ago

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Which Question? All of them?

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Which number represents a repeating decimal? 1/6, 25%, 0.5020202

mafiozo [28]

1/6 is the only one that repeats forever. 0.16666666666etc.

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2 years ago

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Can someone explain this to me? I really need help. Thx!

Gennadij [26K]

Answer:

3 to the 4th power.

Step-by-step explanation:

Basically, here 3 to the 3rd power is 27. Multiplying it by 3 is only adding another power, making it 81, which is the same answer to 3 to the 4th power if that makes sense.

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2 years ago

What is 0.326 & 8.157 & 0.924 & 1.075 in two forms? Im only in 5th grade so nothing really advanced please :)

Alona [7]

7.856 thats the answer bruh

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3 years ago

Which number is NOT in the solution set of x − 9 > 3? A) 11 B) 13 C) 15 D) 17

densk [106]

Answer:

Step-by-step explanation:

Given

x - 9 > 3 ( add 9 to both sides )

x > 12

13, 15 and 17 are all greater than 12

However, 11 is less than 12 and is not in the solution set → A

7 0

3 years ago

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A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey

Lubov Fominskaja [6]

Answer:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

Step-by-step explanation:

For this case we have the following distribution given:

X 0 1 2 3 4 5 6

P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02

For this case we need to find first the expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And replacing we got:

$E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61$

Now we can find the second moment given by:

$E(X^2) =\sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97$

And the variance would be given by:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

8 0

3 years ago