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gregori [183]
3 years ago
10

Use complete sentences to explain how to use linear factors to determine the equation of a polynomial function

Mathematics
2 answers:
Leona [35]3 years ago
8 0

Answer: p(x) = a (x-b)(x-c)(x-d)

Step-by-step explanation:

The first step is to determine the degree of the polynomial.

It shall depend totally on the linear factors given for the polynomial.

If there is one, it is a linear polynomial.

If there are 2, then it is a quadratic polynomial.

If there are three then it shall be a cubic polynomial.

Now let us assume that there are three linear factors.

We multiply those factors and write the polynomial.

If x-b, x-c & x-d are the factors we write

p(x) = (x-b)(x-c)(x-d)

But as we may have a leading coefficient so we write the polynomial as

Then we go on to expand this to get the polynomial in the standard form.

d1i1m1o1n [39]3 years ago
7 0

Answer with Step-by-step explanation:

First we find the degree of polynomial.

Consider two linear factors

(x-a) and (x-b)

Multiplying these two factors to get the polynomial.

p(x)=(x-a)(x-b)=x^2-(a+b)x+ab

There are two linear factors .

Therefore, the degree of polynomial is 2 and the polynomial is quadratic.

Degree of polynomial=Number of linear factors

If the linear factors are three then the polynomial formed by multiplying theses factors .

Then, we get the polynomial of degree 3 and the polynomial is cubic polynomial.

It we have four linear factors.

After multiplying these four factors, we get a polynomial of degree 4.

The polynomial is bi quadratic.

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3 years ago
Which expressions are polynomials?
igor_vitrenko [27]

Option A: z + 1

Option B: 6 + w

Option D: 2 x^{4}-y

Solution:

Let us first define the polynomial.

A polynomial can have constants, variables, exponents and fractional coefficients.

A polynomial cannot have negative exponents, fractional exponents and never divided by a variable.

<u>To find which expressions are polynomial:</u>

Option A: z + 1

By the definition, z + 1 is a polynomial.

It is polynomial.

Option B: 6 + w

By the definition, 6 + w is a polynomial.

It is polynomial.

Option C: y^{2}-\sqrt[3]{y}+4

y^{2}-\sqrt[3]{y}+4=y^{2}-{y}^{1/3}+4

Here, y have fractional exponent.

So, it is not a polynomial.

Option D: 2 x^{4}-y

By the definition, 2 x^{4}-y is a polynomial.

It is polynomial.

Hence z + 1, 6 +w and 2 x^{4}-y are polynomials.

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Answer:

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Step-by-step explanation:

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