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2 years ago

Can someone answer these questions please, i'm having trouble with them

Mathematics

2 answers:

fiasKO [112]2 years ago

4 0

Answer:

1. $686.94

2. $735.03

3. $10707.55

4. $17631.94

5. $19635.72

Step-by-step explanation:

1st Question:

The interest rate is 7% for each year. This means that each year the person has to pay 7% more than the previous amount. So we need to multiply the initial amount by (0.07+1=1.07) in order to get the interest for the first year. if we want to find the second year's interests then we will have to multiply 2 (1.07)'s and so on.

in this case our function is: 600*(1.07)^t=P(t)

when t=2 P(2)=600*(1.07)^2=$686.94

2nd Question:

Function: 600*(1.07)^t=P(t)

when t=3 P(3)=600*(1.07)^3=$735.03

3rd Question:

initial value=$8500

1+0.08=1.08

Function: 8500*(1.08)^t=P(t)

t=3

P(3)=8500*(1.08)^3=$10707.55

4th Question:

initial value=$12000

1+1.08=1.08

t=5

Function: P(t)=12000*(1.08)^t

P(5)=12000*(1.08)^5=$17631.94

5th Question:

Function: 14000*(1.07)^t=P(t)

P(5)=14000*(1.07)^5

P(5)=$19635.72

zepelin [54]2 years ago

4 0

Dang bro did it before me

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A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life

alisha [4.7K]

Answer:

The null hypothesis is $H_0: \mu \leq 10$

The alternative hypothesis is $H_1: \mu > 10$

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

$H_0: \mu \leq 10$

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

$H_1: \mu > 10$

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that $\mu = 10$

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that $n = 45, X = 10.5, s = 1.8$