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2 years ago

PLEASE HURRY!! Will give brainliest!!

Mathematics

2 answers:

nadezda [96]2 years ago

7 0

Answer:

the answer is a

Step-by-step explanation:

Mo worked more than 11 hours this week.

AURORKA [14]2 years ago

5 0

Answer:

A. ("Mo worked more than 11 hours this week. ")

Step-by-step explanation:

Let d represent the value of hours Mo has worked.

d is more than 11 hours because Mo worked more than 11 hours

so it's safe to say...

d>11

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Convert: 6y + y² = x² from rectangular to polar form.

11Alexandr11 [23.1K]

$\bf \textit{Double Angle Identities}
\\ \quad \\
sin(2\theta)=2sin(\theta)cos(\theta)
\\ \quad \\\\
cos(2\theta)=
\begin{cases}
\boxed{cos^2(\theta)-sin^2(\theta)}\\
1-2sin^2(\theta)\\
2cos^2(\theta)-1
\end{cases}\\\\\\
tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\
-------------------------------\\\\$

$\bf 6y+y^2=x^2\implies \cfrac{6y}{x^2}+\cfrac{y^2}{x^2}=1\implies \cfrac{6rsin(\theta )}{[rcos(\theta )]^2}+\cfrac{[rsin(\theta )]^2}{[rcos(\theta )]^2}=1
\\\\\\
\cfrac{6rsin(\theta )}{r^2cos^2(\theta )}+\cfrac{r^2sin^2(\theta )}{r^2cos^2(\theta )}=1\implies 
\cfrac{6sin(\theta )}{rcos^2(\theta )}+\cfrac{sin^2(\theta )}{cos^2(\theta )}=1$

$\bf \cfrac{6sin(\theta )}{rcos^2(\theta )}=1-\cfrac{sin^2(\theta )}{cos^2(\theta )}\implies \cfrac{6sin(\theta )}{1-\frac{sin^2(\theta )}{cos^2(\theta )}}=rcos^2(\theta )
\\\\\\
\cfrac{6sin(\theta )}{cos^2(\theta )\left[ 1-\frac{sin^2(\theta )}{cos^2(\theta )} \right]}=r\implies \cfrac{6sin(\theta )}{cos^2(\theta )-sin^2(\theta )}=r
\\\\\\
\cfrac{6sin(\theta )}{cos(2\theta )}=r$

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2 years ago

Find the next term for the given sequence.52, 45, 38, 31

valkas [14]

The answer is 24. To get to each term, we can see that the value is decreasing by 7. So 31 - 7 = 24

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2 years ago

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Komok [63]

Answer:

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Hope this helps

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2 years ago

Suppose y varies directly with x. When x is 2, y is 20. What is x when y is 50

yuradex [85]

Answer:

Step-by-step explanation:

x = 2 >>> (Multiply by 10) >>> y = 20

x = ? >>> (Multiply by 10) >>> y = 50

50 ÷ 10 = 5

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2 years ago

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arsen [322]

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