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3 years ago

Y’all help meeee imma fail fr!!.!.

Mathematics

1 answer:

sweet [91]3 years ago

7 0

Answer:

Altitude of cylinder = 10 cm

Step-by-step explanation:

Given:

lateral surface area of cylinder = 90 cm²

Circumference of base = 9 cm

Find:

Altitude of cylinder

Computation:

Circumference of base = Circumference of cylinder

So,

2πr = 9

lateral surface area of cylinder = 2πrh

2πrh = 90

We know that; 2πr = 9

So,

9(h) = 90

h = 90 / 9

Altitude of cylinder = 10 cm

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4 years ago

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sp2606 [1]

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3 years ago

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Answer:

Step-by-step explanation:

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4 years ago

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Anastaziya [24]

Answer:

see below

Step-by-step explanation:

by rewriting the function we can see that it has a minimum at

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2 years ago

Find the standard form of the equation of the hyperbola satisfying the given conditions: X intercept +/- 6; foci at (-10,0) and

uysha [10]

Answer:

$\frac{x^{2}}{36} - \frac{y^{2}}{64}=1$

Step-by-step explanation:

Given an hyperbola with the following conditions:

Foci at (-10,0) and (10,0)
x-intercept +/- 6;

The following holds:

The center is midway between the foci, so the center must be at (h, k) = (0, 0).

The foci are 10 units to either side of the center, so c = 10 and $c^2 = 100$
The center lies on the origin, so the two x-intercepts must then also be the hyperbola's vertices.

Since the intercepts are 6 units to either side of the center, then a = 6 and $a^2 = 36.$

$Then, a^2+b^2=c^2\\b^2=100-36=64$

Therefore, substituting $a^2 = 36.$ and $b^2=64$ into the standard form

$\frac{x^{2}}{a^2} - \frac{y^{2}}{b^2}=1\\We \: have:\\ \dfrac{x^{2}}{36} - \dfrac{y^{2}}{64}=1$

4 0

3 years ago