Answer:
depolarization leading to action potentials
Explanation:
The voltage-gated Na+ channels are responsible for rapid depolarization phase of the action potential. Action potential generation require depolarization of neuronal membrane which is acquired by influx of sodium ions through voltage gated sodium ion channels. If the Na+ channels are blocked, there will be no influx of sodium ions to cause depolarization hence action potential will not be generated.
A reaction in which heat energy<span> is absorbed is said to be endothermic. You </span>can<span> show this on simple </span>energy <span>diagrams. For an exothermic change: Notice that in an exothermic change, the </span>products<span> have a </span>lower energy than<span> the </span>reactants<span>.</span>
The lactose-digesting bacteria like to grow on milk agar .Bacillus cereus growth and survival were examined during the production of cheese of the Gouda variety. Approximately 102 B. cereus spores per milliliter of cheese milk were intentionally added to pasteurized milk before it was used to make the cheese in the pilot plant.
"milk agar," in which 2% nonfat powdered milk is added to the agar base. lactose-digesting bacteria like to grow on milk agar. Surface plating on B. cereus selective medium was used to count B. cereus, while lactic acid bacteria were counted on lactic agar and MRS agar (de Man-Rogosa-Sharpe). Samples of the milk before renneting, the curd at cutting, the half-whey removal, the final whey removal, the hooping of the curd, the cheese after pressing, the cheese after brining, after one week, after two weeks, after four weeks, and after six weeks were all taken for microbiological analysis. The growth of lactic acid bacteria during cheese production was unaffected by B. cereus.
Learn more about B. cereus here-
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Answer:
<h2>Recessive to
</h2>
Explanation:
1. As given here, both parents are black, and their 247 progeny out of 333 are black, it clearly indicates that 3/4 progeny is parental phenotype and 1/4 is different type.
2. This clearly show that both parents are heretogyzous, one allele is dominant and one is recessive.
3. Here black is dominant over blue.
4. Dominant allele express them-self in dominant homogyzous as well as heterogyzous condition.
