Answer:
Don't lisen to that the anwer is 0.3125
Step-by-step explanation:
Answer: You can't hear the tone of voice or get clues from body language.
Step-by-step explanation:
When sending emails, the sender and the recipient communicate through a screen, thus each person is unable to see the other when conversing or hear the inflections or emphasis of voice in the message, although we can always attempt to interpret tone. Email allows you to store emails in the inbox or archive and access sent messages, but email lacks the ability to intimately understand specifics such as tone of voice or body language.
Hello there! Thank you for asking your question here at Brainly. I will be assisting you today with how to handle this problem, and will teach you how to handle it on your own in the future.
First, let's evaluate the question.
"The circumference of a circle is 6.28. What is the area of a circle?"
Now, let's remember the different formulas for area and circumference.
The circumference is "2•3.14•r", while the area is "3.14•r•r".
We have our circumference, 6.28.
However, we are looking for the area. Since we have the circumference, we need to narrow down to the radius (so we can solve for the area).
Let's set this up as an equation;
C = 2 • 3.14 • r
Plug in the value for our circumference.
6.28 = 2 • 3.14 • r
Multiply 2 by 3.14 and r to simplify the right side of the equation.
2 • 3.14 • r = 6.28 • r = 6.28r
We're now left with:
6.28 = 6.28r
Divide both sides by 6.28 to solve for r.
6.28 / 6.28 = 1
6.28r / 6.28 = r
We are now left with the radius:
R = 1.
Now, we can solve for the area.
Remember our formula for the area.
A = r • r • 3.14.
Plug in 1 for r.
A = 1 • 1 • 3.14
A = 3.14.
Your area is 3.14 units^2.
I hope this helps, and has prepared you for your future problems in relation to this topic!
Answer:
Ordinary Least Square (OLS) for the multiple regression model involves selecting parameters of a straight line function that will minimize <u>the sum of the squares of the variance in the given dataset and those forecasted by the straight-line function.</u>
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