PLEASE CAN SOMEONE ANSWER THIS <br><br> y=8.2x+459=

the x and y axis are tangent to a circle with radius 3 units. write a standard equation of the circle.

Mekhanik [1.2K]

Given:

The x and y axis are tangent to a circle with radius 3 units.

To find:

The standard form of the circle.

Solution:

It is given that the radius of the circle is 3 units and x and y axis are tangent to the circle.

We know that the radius of the circle are perpendicular to the tangent at the point of tangency.

It means center of the circle is 3 units from the y-axis and 3 units from the x-axis. So, the center of the circle is (3,3).

The standard form of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where, (h,k) is the center of the circle and r is the radius of the circle.

Putting $h=3,k=3,r=3$ , we get

$(x-3)^2+(y-3)^2=3^2$

$(x-3)^2+(y-3)^2=9$

Therefore, the standard form of the given circle is $(x-3)^2+(y-3)^2=9$ .

3 0

2 years ago

In a multiple choice quiz there are 5 questions and 4 choices for each question (a, b, c, d). Robin has not studied for the quiz

Ahat [919]

Answer:

a) There is a 18.75% probability that the first question that she gets right is the second question.

b) There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

c) There is a 10.35% probability that she gets the majority of the questions right.

Step-by-step explanation:

Each question can have two outcomes. Either it is right, or it is wrong. So, for b) and c), we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem we have that:

Each question has 4 choices. So for each question, Robin has a $\frac{1}{4} = 0.25$ probability of getting ir right. So $\pi = 0.25$ . There are five questions, so $n = 5$ .

(a) What is the probability that the first question she gets right is the second question?

There is a 75% probability of getting the first question wrong and there is a 25% probability of getting the second question right. These probabilities are independent.

So

$P = 0.75(0.25) = 0.1875$

There is a 18.75% probability that the first question that she gets right is the second question.

(b) What is the probability that she gets exactly 1 or exactly 2 questions right?

This is: $P = P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{5,1}.(0.25)^{1}.(0.75)^{4} = 0.3955$

$P(X = 2) = C_{5,2}.(0.25)^{2}.(0.75)^{3} = 0.2637$

$P = P(X = 1) + P(X = 2) = 0.3955 + 0.2637 = 0.6592$

There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

(c) What is the probability that she gets the majority of the questions right?

That is the probability that she gets 3, 4 or 5 questions right.

$P = P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{5,3}.(0.25)^{3}.(0.75)^{2} = 0.0879$

$P(X = 4) = C_{5,4}.(0.25)^{4}.(0.75)^{1} = 0.0146$

$P(X = 5) = C_{5,5}.(0.25)^{5}.(0.75)^{0} = 0.001$

$P = P(X = 3) + P(X = 4) + P(X = 5) = 0.0879 + 0.0146 + 0.001 = 0.1035$

There is a 10.35% probability that she gets the majority of the questions right.

6 0

3 years ago

20 PTS! Need help! Please explain! The amount of money a worker makes varies directly with the hourly rate of pay. Worker A earn

Anit [1.1K]

The answer to this question is "B)$126" The hourly pay is 21$

7 0

2 years ago

Read 2 more answers

David, Ben, and Jordan shared stickers in a ratio of 8 : 9 : 10. If Ben had 36 stickers, how many stickers did Jordan have?

pantera1 [17]

Answer:

Jordan had 40 stickers.

Step-by-step explanation:

For this ratio, we have David:Ben:Jordan as 8:9:10, and so we need to make it as a more complex fraction, 8/9/10, now we need a multiplier to get us from 9 stickers of Jordan to 36, like a giant one. The common multiplier in this case is 4, and we know that the values must always stay proportional. We multiply everything by 4,and we get a final ratio of 32:36:40, and since Jordan is the last in the ratio David:Ben:Jordan, Jordan ends up with 40 stickers.

3 0

3 years ago

There are 28 total students in Mr. Flynn’s class. The ratio of his students who are in the play to those who are not in the play

Vanyuwa [196]

About 18 students are in the play

3 0

3 years ago

PLEASE CAN SOMEONE ANSWER THIS y=8.2x+459=