Answer:
Yes
Step-by-step explanation:
Example
x+2 is a factor of 2x+4.
2(x+2) = 2x+4.
Answer:
294 cars.
Step-by-step explanation:
Let x be the number of cars and y be the number of trucks.
We have been given that the first dealership sells a total of 164 cars and trucks. We can represent this information as:

The second dealership sells twice as many cars and half as many trucks as the first dealership. So the number of cars sold by 2nd dealership will be 2x and number of trucks sold by 2nd dealership will be y/2.
Further, the 2nd dealership sold a total of 229 cars and trucks. We can represent this information as:

We can see that total number of cars sold on two dealerships will be
.
We will use substitution method to solve for x. From equation (1) we will get,

Substituting this value in equation (2) we will get,

Now let us have a common denominator.


Upon multiplying both sides of our equation by 2 we will get,





Therefore, the total number of cars sold by two dealerships is 294.
Answer:
18x^2 - 9
Step-by-step explanation:
y = f(x)= 6x^3 - 9x + 4
dy/dx = d/dx(6x^3) - d/dx(9x) + d/dx (4)
=6.d/dx(x^3) - 9.d/dx (x) + d/dx. (4)
=6.3x^2 - 9.1 + 0 =18x^2 - 9
Answer:
The Answer is 76.
Step-by-step explanation:
Given the normal distribution " 10% of employees (rated) exemplary, 20% distinguished, 40% competent, 20% marginal, and 10% unacceptable'', we can see that exemplary employees are top 10% rated employees.
We have the formula for normal distribution:
z=(X-M)÷σ
where z is the <em>minimum z-score </em>for top 10% employee, X is the <em>minimum </em>score for top 10% employee, M is the <em>mean</em> of the score distribution, σ is the <em>standard deviation</em> of the score distribution.
The z-score we are looking for is the value "a" that separates the highest 10% from the lowest 90% i.e. P(z≤a)=0.90
If we look at z-table, corresponding value for a is 1.28155
We can now put the values in the formula:
1.28155=
So X=(1.28155×20)+50=75.631
Therefore minimum score for exemplary employee is 76.