It should be the 3rd one but idk for sure. if its not then its the 3rd one
Answer:
frac{21x^6y^5}{14x^2y^9}
Factor the number =\frac{7\cdot \:3x^6y^5}{14x^2y^9}
Factor the number 14=7. 2 =\frac{7\cdot \:3x^6y^5}{7\cdot \:2x^2y^9}
Cancel\:the\:common\:factor:}\:7 =\frac{3x^6y^5}{2x^2y^9}
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
First, let's rearrange the given equation into something more recognizable. If we add 13 to both sides, we now have the polynomial 
. We can now use the quadratic formula to solve.
Remember that the quadratic formula is
Substitute the numbers from the equation into the formula.
Simplify:
Here, I'm going to assume that there was a mistype in option B because if we divide out the 2 we end up with 
.
Hope this helps!
The classifications of the functions are
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
<h3>How to classify each function accordingly?</h3>
The categories of the functions are given as
- A vertical stretch
- A vertical compression
- A horizontal stretch
- A horizontal compression
The general rules of the above definitions are:
- A vertical stretch --- g(x) = a f(x) if |a| > 1
- A vertical compression --- g(x) = a f(x) if 0 < |a| < 1
- A horizontal stretch --- g(x) = f(bx) if 0 < |b| < 1
- A horizontal compression --- g(x) = f(bx) if |b| > 1
Using the above rules and highlights, we have the classifications of the functions to be
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
Read more about transformation at
brainly.com/question/1548871
#SPJ1
Answer:
-7
Step-by-step explanation:
substitute both x's for 7:
(-8(7)+4)+ (3(7)2+5)
= -54 + 47
= -7
