Answer:
6^-4 ÷ 3^-4
6^-4/3^-4
Since their powers are negative
Flip them both so the negative index is lost.
It now becomes
3^4/6^4
81/1296
=1/16
Answer:
The 4th graph
Step-by-step explanation:
To determine which graph corresponds to the f(x) = \sqrt{x} we will start with inserting some values for x and see what y values we will obtain and then compare it with graphs.
f(1) = \sqrt{1} = 1\\f(2) = \sqrt{2} \approx 1.41\\f(4) = \sqrt{4} = 2\\f(9) = \sqrt{9} = 3
So, we can see that the pairs (1, 1), (2, 1.41), (4, 2), (3, 9) correspond to the fourth graph.
Do not be confused with the third graph - you can see that on the third graph there are also negative y values, which cannot be the case with the f(x) =\sqrt{x}, the range of that function is [0, \infty>, so there are only positive y values for f(x) = \sqrt{x}
3(4x+3) = 12x + 9
A= 3(4x+1)
B= 9 + 12x
C= 7x + 6
D= 12x + 9
E= 12x + 9
Answer: D, E
Hope This Helps✨
Answer:
J(-5,2), A(-5,4), and N(-1,1)
Step-by-step explanation:
