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aev [14]
4 years ago
6

What can be said about the relationships between triangles and circles? Check all that apply.

Mathematics
1 answer:
ycow [4]4 years ago
3 0

Answer:

The answers are:

A. Exactly one circle can be inscribed in a given triangle.

C. Many triangular shapes can be circumscribed about a given circle.

Step-by-step explanation:

I just took the quiz as well. Good luck!

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3 y + 13 equals 2y + 2 equals 5 y - 5
Volgvan
3y+13=2y+2
y+13=2   (subtracting 2y from both sides)
y=-11      (subtracting 13 from both sides)
4 0
4 years ago
4. 10 Unit Test: Surface Area and Volume - Part 1
olga_2 [115]

The shape represented by this solid figure attached is a triangular prism with two triangle base and three rectangular faces.

<h3>What is a solid figure?</h3>

A solid figure is a three dimensional shape having length, width and height. Examples of solid figures are<em> cylinders, cone, pyramid</em> and <em>prism</em>.

The shape represented by this solid figure attached is a triangular prism with two triangle base and three rectangular faces.

Find out more on solid figure at: brainly.com/question/8774322

7 0
3 years ago
What is the answer to this problem?
blagie [28]

Answer:

3/16

Step-by-step explanation:

Multiply both denominators and numerators together, which creates the new fraction.

3 0
4 years ago
HELPP ASAP I WILL GIVE 14 POINTS
jek_recluse [69]

Given:

A box-and-whisker plot of data set.

To find:

The percentage of the data values that are greater than 80.

Solution:

From the given box-and-whisker plot, it is clear that:

Minimum value = 8

First quartile = 60

Median = 68

Third quartile = 80

Maximum value = 92

We know that the 25% the data value are greater than or equal to third quartile because the third quartile divides the data in 75% to 25% and 80 is the third quartile.

Therefore, about 25% of the data values that are greater than 80.

5 0
3 years ago
A cylindrical container has a radius of 0.3 meter and a height of 0.75 meter the container is filled with kerosene. the density
klio [65]

The volume of the cylinder is:

3.14 x 0.3^2 x 0.75 = 0.21 cubic meters.

Multiply the density of the kerosene by the volume of the cylinder:

0.21 x 815 = 17.85 kg.

8 0
3 years ago
Read 2 more answers
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