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Ghella [55]
3 years ago
15

Which of the following is the point and slope of the equation y - 3 = 2(x + 5)?

Mathematics
1 answer:
7nadin3 [17]3 years ago
5 0

Answer:

It would be A) (-5,3) and M = 2


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Hi please help i’ll give brain
NARA [144]

Answer:

The GCF is going to be 20

Step-by-step explanation:

This Is how I find the GCF of 2 numbers. I find the prime factorization first, then I find the common factors and multiply them. Here

The prime factorization of 20, 2 × 2 × 5= 20

The prime factorization of 80, 2 × 2 × 2 × 2 × 5 = 80

The common factors are 2, 2, and 5. We multiply those to get the GCF.

2 × 2 × 5 = 20

7 0
3 years ago
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What is the value of point G on the number line?
olya-2409 [2.1K]

A) because it is 2/3 past 1

8 0
3 years ago
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If the fixed cost is 9000 per year. Variable costs are estimated to be Tk. 60.75 / item. The firm wants to break even if 80 item
Mnenie [13.5K]

9514 1404 393

Answer:

  Tk 173.25

Step-by-step explanation:

The firm will break even if its cost is equal to its revenue. That is, the price of each item sold must equal the cost of producing it. To cover the fixed cost, a share of it must be added to each of the items sold. Then the break-even price for 80 items is ...

  price = variable cost + share of fixed cost

  price = Tk 60.75 +9000/80 = Tk 60.75 +112.50 = Tk 173.25

6 0
3 years ago
What is this plz help me idk
dalvyx [7]
Draw a graph with those points. then draw a vertical line through the graph. if the line passes through twice then it’s not a function if it only passes through once it’s a function.
6 0
3 years ago
A cyclist accelerates from 0 m/s to 8 m/s in 3 seconds. What is his acceleration? Is this acceleration higher than that of a car
77julia77 [94]

The average acceleration of an object is calculated as the final speed minus the initial speed divided by the elapsed time.

So:

a = \frac{V_f-V_0}{T_2-T_1}

Where

V_f= final speed

V_0 = initial speed

T_2-T_1 = elapsed time.

Thus:

The acceleration of the cyclist is:

a = \frac{8-0}{3}

a = 2.667m / s ^ 2

The acceleration of the car is:

a = \frac{30-0}{8}

a = 3.75 m/s^2

The average acceleration of the car is higher than the average acceleration of the cyclist.

7 0
3 years ago
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