The value of side length x is equal 6.05 in
<h3>Perimeter of a Square</h3>
The perimeter of a square is given as the sum of the total sides in the square or 4 multiplied by the side length of the square since they all have equal sides.
Mathematically, this can be written as
![P = 4 *L\\P = 4l\\](https://tex.z-dn.net/?f=P%20%3D%204%20%2AL%5C%5CP%20%3D%204l%5C%5C)
In this given question, the side length is equal to x and the perimeter of the square is given as 24.2in.
Let's substitute the values
![P = 4L\\24.2 = 4L\\but l = x\\24.2 = 4x\\x = 6.05in](https://tex.z-dn.net/?f=P%20%3D%204L%5C%5C24.2%20%3D%204L%5C%5Cbut%20l%20%3D%20x%5C%5C24.2%20%3D%204x%5C%5Cx%20%3D%206.05in)
The side length of the square is equal to 6.05in
Learn more on perimeter of square here;
brainly.com/question/24487155
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complete question
Write and solve an equation to find the unknown side length x (in inches).
Perimeter =24.2 in. assuming the figure is a square
Not sure if you still need the answer
But it's 120+20![\pi](https://tex.z-dn.net/?f=%5Cpi)
Because the 3 boxes in the middle are cubes, all three are 10x10, and perimeter of a cube is each side added up.
All together it would be 40+40+40 which equals 120.
Then for the semi-circles, the perimeter formula is 1/2(
d) d standing for diameter. Since we can tell that the diameter takes up 2 full cubes, we know that the diameter is 20. However since it's a semi-circle we cut that in half. So 10![\pi](https://tex.z-dn.net/?f=%5Cpi)
10
+10
=20![\pi](https://tex.z-dn.net/?f=%5Cpi)
So then your final answer is 120+ 20![\pi](https://tex.z-dn.net/?f=%5Cpi)
I hope my answer was clear enough!
The probability is 1/4 because there are 20 numbers (?/20) and 5 are divisible by four (-4,-8,-12,-16,-20) which makes 5/20 which simplified = 1/4.
Answer:
11yz² and when evaluating we get 22528
Step-by-step explanation:
We have the expression ![11\sqrt{y^{2}z^{4} }](https://tex.z-dn.net/?f=11%5Csqrt%7By%5E%7B2%7Dz%5E%7B4%7D%20%20%7D)
We know that a square root is a 1/2 exponent, so we're going to multiply the exponents of y and z by 1/2.
![11\sqrt{y^{2}z^{4} }= 11y^{2(1/2)}z^{4(1/2)} } =11yz^{2}](https://tex.z-dn.net/?f=11%5Csqrt%7By%5E%7B2%7Dz%5E%7B4%7D%20%20%7D%3D%2011y%5E%7B2%281%2F2%29%7Dz%5E%7B4%281%2F2%29%7D%20%7D%20%20%3D11yz%5E%7B2%7D)
Therefore the expression is rewritten as ![11yz^2](https://tex.z-dn.net/?f=11yz%5E2)
Now we're going to evaluate this expression for y = 8 and z = 16
![11yz^{2} =11(8)(16)^2=88(256)=22528](https://tex.z-dn.net/?f=11yz%5E%7B2%7D%20%3D11%288%29%2816%29%5E2%3D88%28256%29%3D22528)
Thus, when evaluated the result is 22528