What is the value of x in the equation x3=27125 ?

Mathematics

2 answers:

Darya [45]3 years ago

5 0

Answer:

x^3-27125=0

Step-by-step explanation:

Divide them

x3=27125

We move all terms to the left:

x3-(27125)=0

We add all the numbers together, and all the variables

x^3-27125=0

alina1380 [7]3 years ago

4 0

Answer:

x = 30.0462

Step-by-step explanation:

Divide each side by 3 to cancel out the 3 next to x. It should now look like this: x = 30.0462

I hope this helps!

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Step-by-step explanation:

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bogdanovich [222]

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$\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left\{\begin{matrix} \ \ \ \dfrac{x}{y} = \dfrac{5}{7} \\ x^2+y^2 = 1184 \end{matrix}\right. \ \Longrightarrow \ x=\dfrac{5}{7}y } \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left (\dfrac{5}{7}y \right )^2+y^2=1184\ \Longrightarrow\ 25y^2+49y^2=58016 } \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{74y^{2}=58016} \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \ \ \ \ \ y^{2}=784 } \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \ \ \ \ y=\pm\sqrt{784}=\pm28 } \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{ x=\dfrac{5}{7}(\pm 28)=\pm 20 } \end{gathered}$}$

The fraction that satisfies the request is $\bf{\dfrac{20}{28}}$ , since in $\bf{\dfrac{-20}{-28}}$ the negative signs are canceled and the first fraction is obtained.