3 years ago

PLEASE PLEASE HELP!!!

Mathematics

1 answer:

nignag [31]3 years ago

3 0

Answer:

Step-by-step explanation:

$x^{2} \sqrt{x} \sqrt[n]{x} \frac{x}{y} x_{123} \beta \beta \alpha \neq \geq \\ \left \{ {{y=2} \atop {x=2}} \right.$

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In circle J with \text{m} \angle HLK= 30^{\circ}m∠HLK=30

olga2289 [7]

Answer:

The minor arc HK is 60 degrees

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The inscribed angle is half that of the arc it comprises.

$m\angle HLK=\frac{1}{2}(arc\ HK)$

we have

$m\angle HLK=30^o$

substitute the given value

$30^o=\frac{1}{2}(arc\ HK)$

$arc\ HK=60^o$

Remember that the measure of the minor arc must be less than 180 degrees

therefore

The minor arc HK is 60 degrees

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Step-by-step explanation:

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kolezko [41]

Answer:

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Step-by-step explanation:

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3 years ago