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marysya [2.9K]
4 years ago
11

A force equal to 500 N is required to barely move a 100 kg mass on a horizontal surface. Find the static friction coefficient be

tween the object and the surface. Take g=9.8 ms^2.
Physics
1 answer:
Afina-wow [57]4 years ago
8 0

The maximum possible force of static friction between two surfaces is given by:

F = μN

F = max friction force, μ = coefficient of static friction, N = normal force

The normal force N equals the object's weight:

N = mg

m = mass, g = gravitational acceleration

Make a substitution:

F = μmg

Given values:

F = 500N, m = 100kg, g = 9.8m/s²

Plug in and solve for μ:

500 = μ(100)(9.8)

μ = 0.51

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Answer:

<em>The force on each charge = 16 N</em>

Explanation:

From coulombs law,

F = 1/4πε₀(q₁q₂)/d²........................ Equation 1

q₁q₂ = F4πε₀d²...................... Equation 2

Where F = force on the two charges, q₁ = charge on the first body, q₂ = charge on the second body, d = distance of separation, 1/4πε₀ = constant of proportionality.

<em>When d = 1 m, F = 1 N,</em>

<em>Constant: 1/4πε₀ = 9×10⁹ Nm²/C²</em>

<em>Substituting these values into equation 2,</em>

<em>q₁q₂ = 1×1²/9×10⁹ </em>

<em>q₁q₂ = 1/9×10⁹  C²</em>

<em>When d = 1/4 m, q₁q₂ = 1/9×10⁹  C² and 1/4πε₀ = 9×10⁹ Nm²/C²</em>

<em>Substituting these values into equation 1</em>

<em>F =  9×10⁹×1/9×10⁹ /(1/4)²</em>

<em>F = 1/(1/16)</em>

<em>F = 16 N</em>

<em>Therefore the force on each charge = 16 N</em>

<em />

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lisabon 2012 [21]

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Hope that helped! :)

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Answer with Explanation:

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We know that

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Using the formula

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We know that

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In a two planet system, does an increase in planet velocity result in a decreased period?
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Option a is correct.
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4 years ago
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