Answer:
Yellow dwarfs are small, main sequence stars. The Sun is a yellow dwarf. A red dwarf is a small, cool, very faint, main sequence star whose surface temperature is under about 4,000 K. Red dwarfs are the most common type of star. Proxima Centauri is a red dwarf.
Explanation:
Answer:
θ₁ = 3.35 10⁻⁴ rad
, θ₂ = 8.39 10⁻⁵ rad
Explanation:
This is a diffraction problem for a slit that is described by the expression
sin θ = m λ
the resolution is obtained from the angle between the central maximum and the first minimum corresponding to m = 1
sin θ = λ / a
as in these experiments the angle is very small we can approximate the sine to its angle
θ = λ / a
In this case, the circular openings are explicit, so the system must be solved in polar coordinates, which introduces a numerical constant.
θ = 1.22 λ / D
where D is the diameter of the opening
let's apply this expression to our case
indicates that the wavelength is λ = 550 nm = 550 10⁻⁹ m
the case of a lot of light D = 2 mm = 2 10⁻³ m
θ₁ = 1.22 550 10-9 / 2 10⁻³
θ₁ = 3.35 10⁻⁴ rad
For the low light case D = 8 mm = 8 10⁻³
θ₂ = 1.22 550 10-9 / 8 10⁻³
θ₂ = 8.39 10⁻⁵ rad
Answer:
speed of the car before the brakes were apply is 12.35 m/s
Explanation:
given data
accident measured distance = 73 feet = 22.25 m
to find out
speed of car before the brakes
solution
we consider here coefficient of kinetic friction between the road and the tires is 0.35
and we take speed of the car just before skidding = u
and final speed of car will be v = 0
now we apply here work energy theorem
so
0.5 mv² - 0.5 mu² = (- coefficient of kinetic friction × mass × g ) distance .......1
0.5( v² -u² ) = (- coefficient of kinetic friction × g ) distance
put here value and we get
0.5 ( 0 - u² ) = (- 0.35 × 9.8 ) 22.25
solve it we get
u = 12.35
speed of the car before the brakes were apply is 12.35 m/s
A circle is just a very very very special kind of ellipse.
So the correct choice is ' A ' .
