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melisa1 [442]
2 years ago
15

The microwaves in a microwave oven are produced in a special tube called a magnetron. The electrons orbit in a magnetic field of

9.6 x 10^−2 T at a frequency of 2.7 GHz , and as they do so they emit 2.7 GHz electromagnetic waves.
a) If the maximum diameter of the electron orbit before the electron hits the wall of the tube is 2.5 cm, what is the maximum velocity the electrons may have?
Physics
1 answer:
Katena32 [7]2 years ago
8 0

Answer:

Explanation:

For equilibrium of rotating electron in outermost circular path

Centripetal force = force on electron

m v² / r = B q v

v = B q r / m , v is velocity of electron , B is magnetic field, q is charge on electron , r is radius of circular path.

v = 9.6 x 10⁻² x 1.6 x 10⁻¹⁹ x 1.25 x 10⁻² / 9.1 x 10⁻³¹

= 2.1 x 10⁸ m /s

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Two objects, m1 = 0.6 kg and m2 = 4.4 kg undergo a one-dimensional head-on collision
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When two bodies of different masses move together each other and have head on collision, they travel to same or different direction after collision.

The external force is not acting here, so the initial momentum is equal to the final momentum. For inelastic collision, final velocity is the common velocity for both the bodies.

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Given are the two objects, m1 = 0.6 kg and m2 = 4.4 kg undergo a one-dimensional head-on collision. Their initial velocities along the one-dimension path are vi1 = 32.4 m/s [right] and vi2 = 8.6 m/s [left].

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Thus, the velocity after collision is 11.456 m/s.

(b) Kinetic energy lost due to collision will be the difference between the kinetic energy before and after collision.

= [1/2m₁u₁² +1/2m₂u₂² ] - [1/2(m₁ +m₂) v²]

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