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melisa1 [442]
3 years ago
15

The microwaves in a microwave oven are produced in a special tube called a magnetron. The electrons orbit in a magnetic field of

9.6 x 10^−2 T at a frequency of 2.7 GHz , and as they do so they emit 2.7 GHz electromagnetic waves.
a) If the maximum diameter of the electron orbit before the electron hits the wall of the tube is 2.5 cm, what is the maximum velocity the electrons may have?
Physics
1 answer:
Katena32 [7]3 years ago
8 0

Answer:

Explanation:

For equilibrium of rotating electron in outermost circular path

Centripetal force = force on electron

m v² / r = B q v

v = B q r / m , v is velocity of electron , B is magnetic field, q is charge on electron , r is radius of circular path.

v = 9.6 x 10⁻² x 1.6 x 10⁻¹⁹ x 1.25 x 10⁻² / 9.1 x 10⁻³¹

= 2.1 x 10⁸ m /s

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A 0.74 mF capacitor is connected to a standard outlet (rms voltage 82 V, frequency 49 Hz ). Determine the magnitude of the curre
disa [49]

Answer:

I =  26.36 cosω t A

Explanation:

Given that

C=0.74 mF

Vrms= 82 V

Frequency ,f= 49 Hz

We know that ω = 2 π f

ω = 2 x  π x 49

ω = 307.72 rad/s

As we know that voltage given as

V= Vo sinω t

V_o=\sqrt2\ V_{rms}

V_o=\sqrt2\ \times 82\

Vo=115.96 V

V=115.96 sinω t

The current given as

I=C\dfrac{dV}{dt}

I=0.74\times \dfrac{dV}{dt}\ mA

\dfrac{dV}{dt}=115.96\omega cos\omega t

I=0.74\times 115.96\times 307.22 cos\omega t\ mA

I = 26362.67 cosω t mA

I =  26.36 cosω t A

This is the current at time ant time t.

7 0
3 years ago
Assume four 1 kohm resistors are connected so that they form a square. what is the equivalent resistance if the resistance is me
borishaifa [10]
If the resistors are arranged in a shape of a square, then they are in a series type of circuit. This circuit arrangement is a non-branching, one-way flow of electrons. The total resistance in a series circuit is the summation of the individual resistances, If you place the ohmmeter (measures resistance) on two non-adjacent sides, then, you are measuring the resistance of two of the resistors.

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Which of these best describes heat transfer through conduction? A) Heat transfer as electrons are excited in atoms. B) Heat tran
Setler79 [48]
I'd go for D here. It also fits in with the idea of thermal expansion - as something is heated up, molecules vibrate and maybe collide. they vibrate with bigger amplitudes, so taking up more space, so expanding. maybe
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A power plant to represent the need for and use for energy; label it energy production.
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An electron is released from rest on the axis of a uniform positively charged ring, 0.200 m from the ring's center. If the linea
melisa1 [442]

Answer:

Velocity of the electron at the centre of the ring, v=1.37\times10^7\ \rm m/s

Explanation:

<u>Given:</u>

  • Linear charge density of the ring=0.1\ \rm \mu C/m
  • Radius of the ring R=0.2 m
  • Distance of point from the centre of the ring=x=0.2 m

Total charge of the ring

Q=0.1\times2\pi R\\Q=0.1\times2\pi 0.4\\Q=0.251\ \rm \mu C

Potential due the ring at a distance x from the centre of the rings is given by

V=\dfrac{kQ}{\sqrt{(R^2+x^2)}}\\

The potential difference when the electron moves from x=0.2 m to the centre of the ring is given by

\Delta V=\dfrac{kQ}{R}-\dfrac{kQ}{\sqrt{(R^2+x^2)}}\\\Delta V={9\times10^9\times0.251\times10^{-6}} \left( \dfrac{1}{0.4}-\dfrac{1}{\sqrt{(0.4^2+0.2^2)}} \right )\\\Delta V=5.12\times10^2\ \rm V

Let\Delta U be the change in potential Energy given by

\Delta U=e\times \Delta V\\\Delta U=1.67\times10^{-19}\times5.12\times10^{2}\\\Delta U=8.55\times10^{-17}\ \rm J

Change in Potential Energy of the electron will be equal to the change in kinetic Energy of the electron

\Delta U=\dfrac{mv^2}{2}\\8.55\times10^{-17}=\dfrac{9.1\times10^{-31}v^2}{2}\\v=1.37\times10^7\ \rm m/s

So the electron will be moving with v=1.37\times10^7\ \rm m/s

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3 years ago
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