Answer:
6) 2.6 m/s, 31°
7) 9.2 m/s
8) 1.2 s
Explanation:
I'll do #6, #7, and #8 as examples. You can solve #9 using the equation from #7, and #10 using the equation from #8.
6) Take north to be +y and east to be +x.
Given:
vₓ = 2.2 m/s
vᵧ = 1.3 m/s
Find: v
v² = vₓ² + vᵧ²
v² = (2.2 m/s)² + (1.3 m/s)²
v ≈ 2.6 m/s
θ = atan(vᵧ / vₓ)
θ = atan(1.3 / 2.2)
θ ≈ 31°
7) Given:
Δy = -4.3 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: v
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (-9.8 m/s²) (-4.3 m)
v ≈ 9.2 m/s
8) Given:
Δy = -6.7 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
-6.7 m = (0 m/s) t + ½ (-9.8 m/s²) t²
t = 1.2 s
It would be True.....................
Answer:
Explanation:
For this interesting problem, we use the definition of centripetal acceleration
a = v² / r
angular and linear velocity are related
v = w r
we substitute
a = w² r
the rectangular body rotates at an angular velocity w
We locate the points, unfortunately the diagram is not shown. In this case we have the axis of rotation in a corner, called O, in one of the adjacent corners we call it A and the opposite corner A
the distance OB = L₂
the distance AB = L₁
the sides of the rectangle
It is indicated that the acceleration in in A and B are related
we substitute the value of the acceleration
w² r_A = n r_B
the distance from the each corner is
r_B = L₂
r_A =
we substitute
\sqrt{L_1^2 + L_2^2} = n L₂
L₁² + L₂² = n² L₂²
L₁² = (n²-1) L₂²
Answer:
first one is - conduction
second one is - convection
I think <u>conduction </u>moves more easily
Umm the rocks warm up until it becomes a not rock anymore and becomes really hot then it get so hot it starts coming out of a mountain called a volcanoe