Which line has an y-intercept of -2

Mathematics

1 answer:

DiKsa [7]3 years ago

7 0

The y-intercept is found when x is set to 0.

Set x to equal 0 for both equations:

$3(0) - 2y = -6$
$-2y = -6$

Divide both sides by -2:

$y = 3$

The y-intercept of this equation is 3, so the first line does not have the y-intercept of -2.

-
$0 + 2y = -2$
$2y = -2$

Divide both sides by 2:

$y = -1$

The y-intercept of this equation is -1, so the second line does not have the y-intercept of -2.

Neither line has a y-intercept of -2.

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The set of all real numbers can be expressed as the interval $(-\infty, \infty)$ . Note that infinity $\infty$ (or $(- \infty)$ itself isn't a real number. The round brackets indicate that both endpoints are excluded from the from the interval.
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