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2 years ago

2/5, 9/10, 7/5, 19/10, 12/5

1 answer:

8 0

Those sequence could be rewritten as :

4/10 , 9/10 , 14/10 , 19/10 , 24/10

From that sequence, we can see that the difference is 5/10 or a 1/2

hope this helps

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The product of a non-zero rational number and an irrational number can always be written as A.a fraction. B.a terminating decima

a_sh-v [17]

The product of a non-zero rational number and an irrational number is irrational.
Therefore C is the answer.
A, B, and D are all properties of rational numbers. Irrational numbers are ones that can not be written as a ratio, or fraction, using whole numbers. They are non-repeating, non-terminating numbers. Example would be pi.

6 0

2 years ago

Read 2 more answers

Smith cell phone company advertises device for 3 cents per minute plus a monthly fee of $29.95. If sara's phone bill for october

hjlf

$38.95-$29.95= $9
$9= 900¢
900¢/3¢= 300
Ans: She used 300 minutes.

6 0

2 years ago

Help on second question

Anna35 [415]

Answer:

0.36

Step-by-step explanation:

you add the probability's together

quite simple really. -3-

3 0

2 years ago

A new neighborhood activity complex is being built in erie. The perimeter of the rectangular playing field is 256 yards. The len

maw [93]

Answer:

The length of the rectangular playing field is 84 yards and the width is 44 yards

Step-by-step explanation:

Let

x ------> the length of the rectangular playing field

y -----> the width of the rectangular playing field

we know that

The perimeter of the rectangular playing field is equal to

$P=2(x+y)$

$P=256\ yd$

$256=2(x+y)$ ------> equation A

we have that

$x=2y-4$ -----> equation B

Solve the system by substitution

Substitute equation B in equation A and solve for y

$256=2(2y-4+y)$

$128=3y-4$

$3y=128+4$

$3y=132$

$y=44$

Find the value of x

$x=2(44)-4=84$

therefore

The length of the rectangular playing field is 84 yards and the width is 44 yards

4 0

3 years ago

How many even 5-digit numbers can be formed from the numbers 1, 2, 4, 7, 8 if no digit is repeated in a number? A. 72 B. 120 C.

katovenus [111]

Hello,

Let's place the last digit: it must be 2 or 4 or 8 (3 possibilities)

It remainds 4 digits and the number of permutations fo 4 numbers is 4!=4*3*2*1=24

Thus there are 3*24=72 possibilities.

Answer A

If you do'nt believe run this programm

DIM n(5) AS INTEGER, i1 AS INTEGER, i2 AS INTEGER, i3 AS INTEGER, i4 AS INTEGER, i5 AS INTEGER, nb AS LONG, tot AS LONG
tot = 0
n(1) = 1
n(2) = 2
n(3) = 4
n(4) = 7
n(5) = 8
FOR i1 = 1 TO 5
    FOR i2 = 1 TO 5
        IF i2 <> i1 THEN
            FOR i3 = 1 TO 5
                IF i3 <> i2 AND i3 <> i1 THEN
                    FOR i4 = 1 TO 5
                        IF i4 <> i3 AND i4 <> i2 AND i4 <> i1 THEN
                            FOR i5 = 1 TO 5
                                IF i5 <> i4 AND i5 <> i3 AND i5 <> i2 AND i5 <> i1 THEN
                                    nb = ((((n(i1) * 10) + n(i2)) * 10 + n(i3)) * 10 + n(i4)) * 10 + n(i5)
                                    IF nb MOD 2 = 0 THEN
                                        tot = tot + 1
                                    END IF
                                END IF
                            NEXT i5
                        END IF
                    NEXT i4
                END IF
            NEXT i3
        END IF
    NEXT i2
NEXT i1
PRINT "tot="; tot
END

7 0

2 years ago