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Roman55 [17]
3 years ago
11

A circle has a diameter of 4 inches. A square has a side length of 4 inches. What is true about the areas of these two figures?

Math item stem image CLEAR CHECK The areas of the two figures are the same. The area of the circle is greater than the area of the square. The area of the square is greater than the area of the circle. More information is needed to solve the problem.
Mathematics
1 answer:
Nuetrik [128]3 years ago
4 0
The area of the square is greater than the circle: the area of the circle is pi(r)^2 while the area of the square is length times width. The area of the circle is about 12.5 while the area of the square is 16.
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Write an ordered pair for this point (The point is circled in hot pink)
aleksley [76]

Answer:

(-4,0)

Step-by-step explanation:

The circled point is 4 spaces away from the center and it is on the the x-axis so that's why the answer would be (-4,0)

Your welcome! Brainliest???

:D

8 0
3 years ago
Mrs. Clever rolls a number cube once.
Zinaida [17]

Answer:

I think it would be 1 out of 6 or B.

Step-by-step explanation:

I think so because there are 6 sides to a cube and if Mrs.Clever only rolls it once then it would be 1 out of 6.

4 0
3 years ago
Give the equation of the line that is perpendicular to y= (1/2)x -1 and passes through the point (3,4)
nexus9112 [7]

Answer: y = -2x + 10

Step-by-step explanation:

Two lines are said to be perpendicular if the product of their slope = -1, that is , if m_{1} is the slope of the first line and m_{2} is the slope of the second line , if the two lines are perpendicular , then m_{1}m_{2} = -1

The equation of the line given :

y = 1/2x - 1

comparing with the equation of line in slope intercept form

y = mx + c , where m is the slope and c is the y - intercept , it implies that

m_{1} = 1/2

Therefore :

m_{2} = -2

To find the equation of the line with slope -2  and passes through the point ( 3 , 4 ) we will use the formula

y-y_{1} = m (x-x_{1} )

y - 4 = -2 ( x - 3 )

y - 4 = -2x + 6

y = -2x + 6 + 4

y = -2x + 10

7 0
3 years ago
Choose any positive integer. Powers of two here are not very interesting, so choose something else. If the number you have chose
Yakvenalex [24]

Answer:

Step-by-step explanation:

Let the integer be 6 for even and 7 for odd (say)

For 6, we divide by 2, now get 3.  Now we multiply by 3 and add 1 to get 10. Now since 10 is even divide by 5, now multiply by 3 and add 1 to get 16.  Now divide by 2 again by 2 again by 2 again by 2 till we get rid of even numbers.

The result is 1, so multiply by 3 and add 1 we get 4 now divide 2 times by 2 to get 1, thus this result now again repeats after 2 times.

Say if we select off number 3, multiply by 3 and add 1 to get 10 now divide by 5, now repeat the same process as above for 5 until we get 1 and it gets repeated every third time.

Thus whether odd or even after some processes, we get 1 and the process again and again returns to 1.

5 0
3 years ago
1) After a dilation, (-60, 15) is the image of (-12, 3). What are the coordinates of the image of (-2,-7) after the same dilatio
BARSIC [14]

Answer:

a) k = 5; (-10, -35)

Step-by-step explanation:

Given:

Co-ordinates:

Pre-Image = (-12,3)

After dilation

Image = (-60,15)

The dilation about the origin can be given as :

Pre-Image(x,y)\rightarrow Image(kx,ky)

where k represents the scalar factor.

We can find value of k for the given co-ordinates by finding the ratio of x or y co-ordinates of the image and pre-image.

k=\frac{Image}{Pre-Image}

For the given co-ordinates.

Pre-Image = (-12,3)

Image = (-60,15)

The value of k=\frac{-60}{-12}=5

or k=\frac{15}{3}=5

As we get k=5 for both ratios i.e of x and  y co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.

To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.

Pre-Image(-2,-7)\rightarrow Image((-2\times5),(-7\times 5))

Pre-Image(-2,-7)\rightarrow Image(-10,-35) (Answer)

7 0
3 years ago
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