Width be X, length is X+15
area of garden = x(x+15)
area of sidewalk = x(x+15) - (x-4)(x+11) = 632
X^2 + 15X - X^2 - 7X + 44 = 632
8X = 632-44 =588
X= 73.5 >> WIDTH and LENGTH = 88.5
HOPE IT HELPED
(1/3) / (2/7) = x / 1
cross multiply
(2/7)(x) = (1/3)(1)
2/7x = 1/3
x = 1/3 * 7/2
x = 7/6 = 1 1/6 liters
Let 
be the legs of the triangle, with ![x[tex]\mathrm{area}_{\rm square} = y^2](https://tex.z-dn.net/?f=x%5Btex%5D%5Cmathrm%7Barea%7D_%7B%5Crm%20square%7D%20%3D%20y%5E2)
The square has 3 times the area of the triangle, so
Meanwhile, in the triangle we have
Now,
B :81 EXPLANATION
The angle with the greatest measure corresponds to the longest:
Since we know the three side lengths, we use the cosine rule to obtain;
{a}^{2} = {b}^{2} + {c}^{2} - 2bc \cos(A)
where a=21, b=18 and c=14
{21}^{2} = {18}^{2} + {14}^{2} - 2 \times 18 \times 14\cos(A)
44 1= 324+ 196 - 504\cos(A)
44 1= 520 - 504\cos(A)
44 1 - 520 = - 504\cos(A)
- 79 = - 504\cos(A)
\cos(A) = 0.1567
A = \cos ^{ - 1} (0.1567) = 80.98 \degree
