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Arturiano [62]
3 years ago
5

When writing 6,020,000 in scientific notation, it is correctly written as: 6.02 x 106 6.02 x 10-6 602. x 106 0.602 x 10-8

Chemistry
2 answers:
larisa [96]3 years ago
8 0

6.02 x 10^6 is correct it's not negative because youre moving in the positive direction in terms of sci not.

alexgriva [62]3 years ago
6 0
The answer is 6.02x 10^-6
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MA_775_DIABLO [31]

Answer:

0.488atm = Pressure Kr

Explanation:

The total pressure in a mixture of gases could be defined as the sum of the partial pressures of a mixture. For the mixture of gases in the problem:

Total pressure = Pressure He + Pressure Ar + Pressure Ne + Pressure Xe + Pressure Kr

Converting the total pressure to atm:

1252.5mm Hg * (1atm / 760 mmHg) = 1.648 atm

Replacing:

1.648atm = 0.32atm + 0.21atm + 0.44atm + 0.19atm + Pressure Kr

<h3>0.488atm = Pressure Kr</h3>
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Blood test can be used to check a person's blood glucose and hormone levels. The tabular column given below shows the result of
Anastasy [175]

Answer:

Explanation:

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2 years ago
What is the composition, in atom percent, of an alloy that contains a) 44.5 lbm of silver, b) 84.7 lbm of gold, and c) 7.3 lbm o
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<u>Answer:</u> The atom percent of silver, gold and copper in the alloy is 43.08 %, 44.93 % and 11.99 % respectively

<u>Explanation:</u>

To convert the given masses into grams, we use the conversion factor:

1 lb = 453.6 grams

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}    ......(1)

To calculate the atom percent of substance in sample, we use the equation:

\%\text{ composition of substance}=\frac{\text{Moles of substance}\times N_A}{\text{Total moles of sample}\times N_A}\times 100     ......(2)

where,

N_A = Avogadro's number

  • <u>Moles of Silver:</u>

Mass of silver = 44.5 lb = 20185.2 grams

We know that:

Molar mass of silver = 107.87 g/mol

Putting values in equation 1, we get:

\text{Moles of silver}=\frac{20185.2g}{107.87g/mol}=187.12mol

  • <u>Moles of Gold:</u>

Mass of gold = 84.7 lb = 38419.9 grams

We know that:

Molar mass of gold = 196.97 g/mol

Putting values in equation 1, we get:

\text{Moles of gold}=\frac{38419.9g}{196.97g/mol}=195.05mol

  • <u>Moles of Copper:</u>

Mass of copper = 7.3 lb = 3311.3 grams

We know that:

Molar mass of copper = 63.55 g/mol

Putting values in equation 1, we get:

\text{Moles of copper}=\frac{3311.3g}{63.55g/mol}=52.10mol

Total moles of the sample =

  • <u>For Silver:</u>

Moles of silver = 187.12 moles

Total moles = [187.12 + 195.05 + 52.10] = 434.27 moles

Putting values in equation 2, we get:

\%\text{ composition of silver}=\frac{187.12\times N_A}{434.27\times N_A}\times 100\\\\\%\text{ composition of silver}=43.08\%

  • <u>For Gold:</u>

Moles of gold = 195.05 moles

Total moles = [187.12 + 195.05 + 52.10] = 434.27 moles

Putting values in equation 2, we get:

\%\text{ composition of gold}=\frac{195.05\times N_A}{434.27\times N_A}\times 100\\\\\%\text{ composition of gold}=44.93\%

  • <u>For Copper:</u>

Moles of copper = 52.10 moles

Total moles = [187.12 + 195.05 + 52.10] = 434.27 moles

Putting values in equation 2, we get:

\%\text{ composition of copper}=\frac{52.10\times N_A}{434.27\times N_A}\times 100\\\\\%\text{ composition of copper}=11.99\%

Hence, the atom percent of silver, gold and copper in the alloy is 43.08 %, 44.93 % and 11.99 % respectively

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3 years ago
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