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3 years ago

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A rocket travels at a rate of 160 meters in 3 seconds. What is the speed of the rocket in meters per second? Plz Help!! A.60 m/s

ec B.53 1/3 m/sec C.65 1/4 m/sec D.480 m/sec

1 answer:

jekas [21]3 years ago

4 0

Answer:

the answer is B

Step-by-step explanation:

do 160/3

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If B is the midpoint of AC, and AC= 8x-20, find BC.

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Answer:

BC = 4x-10

Step-by-step explanation:

$\because B$ is the midpoint of AC.

$\therefore BC = \frac{1}{2} AC$

$\therefore BC = \frac{1}{2} (8x-20)$

$\therefore BC = \frac{1}{2} \times 2(4x-10)$

$\huge \purple {\boxed {\therefore BC = 4x-10}}$

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What potential rational root is -2/5

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180

Step-by-step explanation:

180 is the left

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Add and subtract rational numbers without common denominators. Show work! 1. 7/4 - 3/2 - 2/5 = 2. - 5/16 + 3/4 + 1/8 = 3. 3/4 -

alukav5142 [94]

$\dfrac{7}{4} - \dfrac{3}{2} - \dfrac{2}{5}$

$= \dfrac{7 \times 5}{4 \times 5} - \dfrac{3 \times 10}{2 \times 10} - \dfrac{2 \times 4}{5 \times 4}$

$= \dfrac{35}{20} - \dfrac{30}{20} - \dfrac{8}{20}$

$= \dfrac{35-30-8}{20}$

$= \dfrac{3}{20}$

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$-\dfrac{5}{16} + \dfrac{3}{4} + \dfrac{1}{8}$

$= -\dfrac{5}{16} + \dfrac{3 \times 4}{4 \times 4} + \dfrac{1 \times 2}{8 \times 2}$

$= -\dfrac{5}{16} + \dfrac{12}{16} + \dfrac{2}{16}$

$= \dfrac{-5+ 12 + 2}{16}$

$= \dfrac{9}{16}$

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$\dfrac{3}{4} - \dfrac{1}{3} - \dfrac{7}{12}$

$= \dfrac{3 \times 3}{4 \times 3} - \dfrac{1 \times 4}{3 \times 4} - \dfrac{7}{12}$

$= \dfrac{9}{12} - \dfrac{4}{12} - \dfrac{7}{12}$

$= \dfrac{9 - 4 - 7}{12}$

$= -\dfrac{2}{12}$

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$\dfrac{2}{9} - \dfrac{2}{12} - \dfrac{2}{3}$

$= \dfrac{2}{9} - \dfrac{1}{6} - \dfrac{2}{3}$

$= \dfrac{2 \times 2}{9 \times 2} - \dfrac{1 \times 3}{6 \times 3} - \dfrac{2 \times 6}{3 \times 6}$

$= \dfrac{4}{18} - \dfrac{3}{18} - \dfrac{12}{18}$

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3 years ago

If you know anything about combining equations, specifically subtracting, can you please help me :)

Rufina [12.5K]

Answer:

5x - 2y = -2

Step-by-step explanation:

When subtracting one equation from the other, we are essentially just subtracting the left side of the second equation from the left side of the first equation and doing the same thing with the two right sides.

Here, we are subtracting (-7x + 3y) from (-2x + y):

(-2x + y) - (-7x + 3y)

Let's get rid of these parentheses. Remember that when we have a subtraction sign before a parentheses, we need to distribute a -1 to each term within those parentheses:

(-2x + y) - (-7x + 3y) = -2x + y + 7x - 3y = -2x + 7x + y - 3y = 5x - 2y

Now on the right side, we're subtracting 2 from 0:

0 - 2 = -2

Put it all together:

5x - 2y = -2

Hope this helps!

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