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3 years ago

5

Which expression is equivalent to 4(2p+4q)

1 answer:

Alina [70]3 years ago

4 0

Answer:

8p+16q

hope this helps

4x2p=8p

4x4q=16q

You might be interested in

Find dy/dx at (0,0) if x^2cosy-sin(y+4x)+ln(1+x)=0

Ksenya-84 [330]

$x^2\cos y-\sin(y+4x)+\ln(1+x)=0$

Differentiate both sides with respect to $x$ , treating $y$ as a function of $x$ :

$2x\cos y-x^2\sin y\dfrac{\mathrm dy}{\mathrm dx}-\cos(y+4x)\left(\dfrac{\mathrm dy}{\mathrm dx}+4\right)+\dfrac1{1+x}=0$

$2x\cos y-4\cos(y+4x)-\left(x^2\sin y+\cos(y+4x)\right)\dfrac{\mathrm dy}{\mathrm dx}+\dfrac1{1+x}=0$

$\left(x^2\sin y+\cos(y+4x)\right)\dfrac{\mathrm dy}{\mathrm dx}=2x\cos y-4\cos(y+4x)+\dfrac1{1+x}$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x\cos y-4\cos(y+4x)+\frac1{1+x}}{x^2\sin y+\cos(y+4x)}$

At the point (0, 0), the derivative is

$\dfrac{\mathrm dy}{\mathrm dx}(0,0)=\dfrac{0-4\cos0+1}{0+\cos0}=-3$

3 0

4 years ago

If a and b are two angles in standard position in Quadrant I, find cos(a+b) for the given function values. sin a=15/17and cos b=

tensa zangetsu [6.8K]

The value of $cos(a+b)$ for the angles $a$ and $b$ in standard position in the first quadrant is $-\frac{36}{85}$

We need to find the value of $cos(a+b)$ . To proceed, we need to use the compound angle formula

<h3>Cosine of a sum of two angles</h3>

The cosine of the sum of two angles $a$ and $b$ is given below

$cos(a+b)=cos(a)cos(b)-sin(a)sin(b)$

We are given

$sin(a)=\dfrac{15}{17}\\\\cos(b)=\dfrac{3}{5}$

We need to find $sin(b)$ and $cos(a)$ , using the identity

$sin^2(\theta)+cos^2(\theta)=1$

<h3>Find sin(b)</h3>

To find $sin(b)$ , note that

$sin^2(b)+cos^2(b)=1\\\\\implies sin(b)=\sqrt{1-cos^2(b)}$

substituting $\frac{3}{5}$ for $cos(b)$ in the identity, we get

$sin(b)=\sqrt{1-cos^2(b)}\\\\=\sqrt{1-\left(\dfrac{3}{5}\right)^2}=\dfrac{4}{5}$

<h3>Find cos(a)</h3>

To find $cos(a)$ , note that

$sin^2(a)+cos^2(a)=1\\\\\implies cos(a)=\sqrt{1-sin^2(a)}$

substituting $\frac{15}{17}$ for $sin(a)$ in the identity, we get

$cos(a)=\sqrt{1-sin^2(a)}\\\\=\sqrt{1-\left(\dfrac{15}{17}\right)^2}=\dfrac{8}{17}$

<h3>Find the value of cos(a+b)</h3>

We can now make use of the formula

$cos(a+b)=cos(a)cos(b)-sin(a)sin(b)$

to find $cos(a+b)$ .

$cos(a+b)=cos(a)cos(b)-sin(a)sin(b)\\\\=\dfrac{8}{17}\cdot\dfrac{3}{5}-\dfrac{15}{17}\cdot\dfrac{4}{5}=-\dfrac{36}{85}$

Learn more about sine and cosine of compound angles here brainly.com/question/24305408

8 0

2 years ago

Express this number in scientific notation 763 thousandths

yan [13]

It would be 763 x 10^-4

3 0

4 years ago

The scores on a statistics exam have a normal distribution and have a mean of 99 and a standard deviation of 11. One individual’

olga_2 [115]

Answer:

2.64

Step-by-step explanation:

The z score is calculated as

z=(x-mean)/Sd

The mean of scores of statistics exam=μ=99

The standard deviation of scores of statistics exam=σ=11

Individual's score in statistics exam=x=128

z=128-99/11=29/11=2.64

Hence, the z score of individual score is 2.64.

3 0

3 years ago

A man buys a TV. The total cost is $2,500, and the sales commission is 8%. How much should the salesperson get as commission for

Margaret [11]

Answer:

$200

Step-by-step explanation:

First Change the percent to a decimal

In this case the percent was %8, change it into a decimal; 8%=.08

Next multiply 2,500 x .08 which gives you 200

The answer is $200! Hope this helps!.

5 0

3 years ago