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3 years ago

8/9÷3= 7/8 1/5 8/27 2/3

Mathematics

1 answer:

natima [27]3 years ago

4 0

8/9 divided by 3 = 8/27

have a wonderful day! the steps are down below! :)

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The stemplot below represents the number of bite-size snacks grabbed by 32 students in an activity for a statistics class. A ste

Karolina [17]

The percentage of this number of snacks grabbed that is greater than 29, as represented by the stem plot is calculated as: A. 16%.

<h3>How to Solve a Stem Plot?</h3>

In a stem plot, each data point is represented as a stem and a leaf, for example, 42 is represented as 4 | 2 on the stem plot.

Given the stem plot for the data of the number of bite-size snacks grabbed by 32 students, the number of snacks grabbed that is greater than 29 are: 32, 32, 34, 38, and 42.

This is 5 out of the total number of the students, which is 32.

Thus, the percentage of this number of snacks grabbed that is greater than 29 would be calculated as:

5/32 × 100 = (5 × 100)/32

= 500/32

= 15.625%

Approximated to the nearest tenth, we would have 16%.

Therefore, the percentage of this number of snacks grabbed that is greater than 29, as represented by the stem plot is: A. 16%.

Learn more about the stem plot on:

brainly.com/question/8649311

#SPJ1

6 0

1 year ago

Is this answer correct

Kobotan [32]

Yes, that looks right.

6 0

3 years ago

A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a

Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 = 0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = $2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750$

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

$W_2 = \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5$

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0

2 years ago

100.00 decreased by 20%<br> Please help

Charra [1.4K]

Answer: If Percentage decrease % = 20%, (1 - Percentage decrease %) = 1 - 20% = 100/100 - 20/100 = 80/100 = 0.8 => Percentage decreased number = 0.8 × Initial value

Step-by-step explanation: Number 100 decreased by 20% (20 percent) of its value (percentage decrease) and calculated absolute change (actual difference)

6 0

2 years ago

What is the y intercept of the linear equation x

spin [16.1K]

x isn't a linear equation, it's just a variable or an expression or a letter of the alphabet.

x = 0 is a linear equation and is a line in the Cartesian plane. In fact, it's the y axis itself.

So every point on the line x=0 is a y intercept.

There is no "the" y intercept, no unique y intercept.

4 0

3 years ago

Read 2 more answers

8/9÷3= 7/8 1/5 8/27 2/3​

8/9÷3= 7/8 1/5 8/27 2/3