Answer:
43.0°
Step-by-step explanation:
cos∅=adj/hyp
cos∅=60/82
∅=cos-1 60/82
∅=cos-1 0.731707317073
∅=42.97028393174°
Round: 43.0°
well, if that function f(x) were to be continuos on all subfunctions, that means that whatever value 7x + k has when x = 2, meets or matches the value that kx² - 6 has when x = 2 as well, so then 7x + k = kx² - 6 when f(2)
![f(x)= \begin{cases} 7x+k,&x\leqslant 2\\ kx^2-6&x > 2 \end{cases}\qquad \qquad f(2)= \begin{cases} 7(2)+k,&x\leqslant 2\\ k(2)^2-6&x > 2 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ 7(2)+k~~ = ~~k(2)^2-6\implies 14+k~~ = ~~4k-6 \\\\\\ 14~~ = ~~3k-6\implies 20~~ = ~~3k\implies \cfrac{20}{3}=k](https://tex.z-dn.net/?f=f%28x%29%3D%20%5Cbegin%7Bcases%7D%207x%2Bk%2C%26x%5Cleqslant%202%5C%5C%20kx%5E2-6%26x%20%3E%202%20%5Cend%7Bcases%7D%5Cqquad%20%5Cqquad%20f%282%29%3D%20%5Cbegin%7Bcases%7D%207%282%29%2Bk%2C%26x%5Cleqslant%202%5C%5C%20k%282%29%5E2-6%26x%20%3E%202%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%207%282%29%2Bk~~%20%3D%20~~k%282%29%5E2-6%5Cimplies%2014%2Bk~~%20%3D%20~~4k-6%20%5C%5C%5C%5C%5C%5C%2014~~%20%3D%20~~3k-6%5Cimplies%2020~~%20%3D%20~~3k%5Cimplies%20%5Ccfrac%7B20%7D%7B3%7D%3Dk)
Answer: The slope is 4/9 or -4/-9.
Step-by-step explanation:
(1,5)
(10,9) Find the difference in the y values and divide it by the difference in the x values.
5-9= -4
1- 10= -9
-4/-9= 4/9
so the slope is 4/9
Using the slope we could also find the y-intercept and write the equation.
5=4/9 (1) + b where b is the y-intercept
5= 4/9 + b
-4/9 -4/9
b= 41/9
Now we will have the equation y= 4/9 + 41/9
Answer:
As x decreases, h increases (but never touches)
As x increases, h decreases (but never touches)
Step-by-step explanation:
If you graphed the exponential, you would be able to see that it is stuck in the 3rd quadrant.
Domain: (negative infinity, 1)
Range: (negative infinity, 0)
