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Irina18 [472]
3 years ago
7

What is the height of the following triangle if the area is 60 square meters? Do not round your answer.

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
5 0

Answer: Height = 8 m

Step-by-step explanation: We have to find h...

We're given two values

A = 60

B = 15

60 is equal to 1/2 x 15

Solve for h:

h = 60 / (1/2 x 15)

h = 60 divided by 7.5

h = 8

I hope this helps!

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What is the missing dimension of a rectangle or prism with the following dimensions and volume? Length 3 cm width 5 cm volume 45
olasank [31]
Hello! 

In order to find out the volume of any prism, you are to do length x width x height.

Because we only know the length and the width, we can multiply those to get started. 3 x 5 is 15, so we know that's what we can start with.

Because we know the volume, all we have to do is do h x 15 = volume (45). Now, what is height?

In order to find the height, we must find a number that, when multiplied by 15, equals 45. 

So we can try out 3, which when multiplied by 15, equals 45. 

That means 3 is your height.

Hope I helped! :)
3 0
3 years ago
Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )
Zina [86]

Answer:

\purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

Step-by-step explanation:

\cos( \alpha ) =  \frac{ \sqrt{6} }{6}  =  \frac{1}{ \sqrt{6} }  \\  \\  \therefore \:  \sin( \alpha )  =  \sqrt{1 -  { \cos}^{2} ( \alpha ) }  \\  \\  =  \sqrt{1 -  \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} }  \\  \\ =  \sqrt{1 -  {\frac{1}{ {6} }}}  \\  \\ =  \sqrt{ {\frac{6 - 1}{ {6} }}}   \\  \\  \red{\sin( \alpha ) =  \sqrt{ { \frac{5}{ {6} }}} } \\  \\  \tan( \alpha ) =  \frac{\sin( \alpha ) }{\cos( \alpha ) }  =  \sqrt{5}  \\  \\ \sin( \beta )  =  \frac{ \sqrt{2} }{4}  \\  \\  \implies \: \cos( \beta )  =   \sqrt{ \frac{7}{8} }  \\  \\ \tan( \beta )  =  \frac{\sin( \beta ) }{\cos( \beta ) } =  \frac{1}{ \sqrt{7} }   \\  \\  \tan( \alpha  -  \beta ) =  \frac{ \tan \alpha  -  \tan \beta }{1 +  \tan \alpha .  \tan \beta}  \\  \\  =  \frac{ \sqrt{5} -  \frac{1}{ \sqrt{7} }  }{1 +  \sqrt{5} . \frac{1}{ \sqrt{7} } }  \\  \\  =  \frac{ \sqrt{35} - 1 }{ \sqrt{7}  +  \sqrt{5} }  \\  \\  \purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

8 0
3 years ago
Let X=[10 -3] and y=[-1 -5] then the distance between X and y is​
slavikrds [6]

Answer:

[11 2]

Step-by-step explanation:

10 to -1 is 11 and-3 to -5 is 2 therfore you have the distance of 11 and 2

3 0
3 years ago
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