I hope this helps you
sec Q=1/cos Q
2=1/cos Q
cos Q= 1/2
Q=30+2.pi.n
Q=330+2.pi.n
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Answer:
x2 +2x−xy when x = 250 and y = −120 ... sic Algebra: Patterns and Equations (13:18)
Step-by-step explanation:
Answer:
The ladder is 4.86 foot from the base of the wall .
Step-by-step explanation:
Given as :
The length of the ladder = 28 ft
The ladder makes angle of 80° with the ground
Let The distance of the ladder from the foot of the wall = x ft
Now, From Triangle BAC
Cos angle = 
I.e Cos 80° = 
Or, 0.1736 = 
Or, x = 0.1736 × 28
∴ x = 4.86 foot
So, The distance of ladder from wall base = x = 4.86 foot
Hence The ladder is 4.86 foot from the base of the wall . Answer
Let gradient of original line = m = 1/6
Gradient of line perpendicular to this = -1/m = -6
(Gradient = slope)
Assuming that there are N lanes and runners are running in the middle of each lane,
width of each lane = (1/N) [m]turning of first lane = π×(R+(1/N)×(1/2))
turning of second lane = π×(R+((1/N)×(1/2))+(1/N))
you can get the difference in turning lane simply by subtracting turning of first lane from turning of second lane.
If i worked the problem correctly, it should be π×(1/N) meter difference between each lane