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quester [9]
3 years ago
10

A school bus has 25 seats, with 5 rows of 5 seats. 15 students from the first grade and 5 students from the second grade travel

in the bus. How many ways can the students be seated if all of the second-grade students occupy the first row?
Mathematics
1 answer:
kow [346]3 years ago
6 0

Answer:

5P5×20P15

Step-by-step explanation:

A school bus has 25 seats, with 5 rows of 5 seats.

15 students from the first grade and 5 students from the second grade travel in the bus.

second-grade students occupy the first row.

The 5 students of second grade are to be seated in 5 seats,this can be done in:

5P5 ways where P is the permutation

Now 15 students from first grade are to be arranged in remaining 20 seats

This can be done in:

20P15 ways

Hence, total ways student can be seated is:

5P5×20P15

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jeka57 [31]

Answer:

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Step-by-step explanation:

#6:

(5,7) and (25,3)

3-7/ 25-5 = -1/5

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( 6,4) and (12,8)

8-4/ 12-6 = 2/3

i hope this helped! :D

5 0
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Answer:

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Step-by-step explanation:

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8 0
2 years ago
Read 2 more answers
Line A goes through the points (1, 5) and (-1, 9). Line B goes through the points (0, 2) and (4, -6). Which of the following sta
Delvig [45]
B is correct. Explanation Below:
---
Line A never intersects Line B, as they are parallel lines-the slopes are the same-and parallel lines never intersect. 
Line A's Slope: (9-5)/(-1-1) = -2
Line B's Slope: (-6-2)/(4-0) = -2
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Hope this helps!
7 0
3 years ago
If f(x) = x2 + 7, what is the value of f(3)?
Mazyrski [523]
Plug in 3 for f(x)
f(3)=(3)²+7
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Hoped this helped!
3 0
3 years ago
Algebra Linear Equations City Task (1)
Bogdan [553]

Answers:

1) Graph Line 1

a) Graph: Please, see the attached graph.

b) (Line 1) Main Street (Equation in slope intercept form): y=(1/3)x+4  

2) Graph Line 2

a) Graph: Please, see the attached graph.

b) Y intercept: (0,10)  

c) X intercept: (5,0)

d) (Line 2) Street Equation in Standard Form: y+2x=10

3) Grap Line 3

a) Graph: Please, see the attached graph.

b) (Line 3) Street Equation in Point Slope Form: <u>y-3=(5/3)(x+3)</u>

Street Equation in Slope Intercept Form: <u>y=(5/3)x+8</u>


Solution:

1) Graph Line 1: (Main Street)

a) Graph the line formed from the two given points (9,7) (-9,1)

Please, see the attached graph.

b) Find the street equation in slope intercept form

P1=(9,7)=(x1,y1)→x1=9, y1=7

P2=(-9,1)=(x2,y2)→x2=-9,y2=1

m=(y2-y1)/(x2-x1)

m=(1-7)/(-9-9)

m=(-6)/(-18)

m=6/18

m=(6/6)/(18/6)

m=1/3

Point Slope form:

y-y1=m(x-x1)

y-7=(1/3)(x-9)

Slope Intercept Form:

y-7=(1/3)x-(1/3)(9)

y-7=(1/3)x-(1)(9)/3

y-7=(1/3)x-9/3

y-7=(1/3)x-3

y-7+7=(1/3)x-3+7

y=(1/3)x+4


2) Graph Line 2

a) Graph the line given the x and y intercepts

y intercept: 10

x intercept: 5

Please, see the attached graph

b) Y intercept  

y intercept: b=10

Y intercept: (0,b)→Y intercept: (0,10)

c) X intercept

x intercept: a=5

X intercept: (a,0)→X intercept: (5,0)

d) Find the Street Equation in Standard Form

P1=(0,10)=(x1,y1)→x1=0, y1=10

P2=(5,0)=(x2,y2)→x2=5, y2=0

m=(y2-y1)/(x2-x1)

m=(0-10)/(5-0)

m=(-10)/(5)

m=-2

Point Slope Form:

y-y1=m(x-x1)

y-10=(-2)(x-0)

y-10=(-2)(x)

y-10=-2x

Standard Form:

y-10+10+2x=-2x+10+2x

y+2x=10


3)  Graph Line 3

a) Graph the line given a point and the slope. (-3,3); m=5/3

Point 1: P1=(-3,3)=(x1,y1)→x1=-3, y1=3

Slope: m=5/3

m=dy/dx

5/3=dy/dx→dy=5, dx=3

Point 2: P2=(x2,y2)

x2=x1+dx→x2=-3+3→x2=0

y2=y1+dy→y2=3+5→y2=8

Point 2: P2=(x2,y2)→P2=(0,8)

Please, see the attached graph.

b) Find the Street Equation in Point Slope Form

Point Slope Form:

y-y1=m(x-x1)

y-3=(5/3)(x-(-3))

y-3=(5/3)(x+3)

Slope Intercept Form:

y-3=(5/3)x+(5/3)(3)

y-3=(5/3)x+(5)(3)/3

y-3=(5/3)x+15/3

y-3=(5/3)x+5

y-3+3=(5/3)x+5+3

y=(5/3)x+8

3 0
3 years ago
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