Answer:
linear
Step-by-step explanation:
The x-values all differ by 1, which is to say they are equally-spaced. The corresponding y-values all differ by -3. When (first) differences of equally-spaced values of y are constant, the function is of first degree, which is to say it is linear.
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If second differences are non-zero and constant, the function is of second degree, quadratic.
( 0,0 ) is not the solution of the first inequality y≤x² +x-4 but ( 0,0) is the solution for the second inequality y <x²+2x+1.
<h3>What is inequality?</h3>
The relation between two expressions that are not equal, employing a sign such as ≠ ‘not equal to’, > ‘greater than, or < ‘less than’
Finding the solution for the inequality is as follows:-
y ≤ x² +x-4 by putting x and y equal to 0.
0 ≤ 0 + 0 -4
0 ≤ - 4
This is incorrect so (0,0) can not be the solution for this inequality.
y < x²+2x+1.
0 < 0 + 0 + 1
0 < 1
This inequality is showing the solution for (0,0)
Therefore ( 0,0 ) is not the solution of the first inequality y≤x² +x-4 but ( 0,0) is the solution for the second inequality y <x²+2x+1.
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Answer:
662.433221
Step-by-step explanation:
907.07 × 1.09 × 0.67
A. If you disassemble the shapes and add the numbers, you can get the answer :).
<h3>
Answer: x = 11</h3>
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Work Shown:
Those are the two possible solutions
. We need to check each possible solution.
Plug in x = 11 then simplify. If we get the same number on both sides, then x = 11 is confirmed.
We get 11 on both sides, so the solution x = 11 is confirmed.
Repeat for x = 6 as well
We do not get the same thing on both sides, so x = 6 is not a solution. We consider this extraneous.
