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Gennadij [26K]
3 years ago
9

Solve this equation 2(x+3)=x-4​

Mathematics
1 answer:
horrorfan [7]3 years ago
5 0

Answer: The answer is x = -10

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Write an equation of a line that is parallel to y=2x-5 that passes through the point (2,6).
inessss [21]

Answer: Parallel lines have the same slope

y = 2x +b

Use the given point (2, 5)

5 = 2(2) +b

b = 5 -4 = 1

The equation of the line is

y = 2x +1

Note general form of the slope-intercept form of a line is y = mx +b, where m is the slope and b is the y-axis intercept

Step-by-step explanation:

3 0
3 years ago
A rectangular board is 1.5 meters long and 0.8 meters wide. What is the area of the board in square millimeters? Do not round yo
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Convert 1.5 and 0.8 from meters to millimeters,

1500*800,

A=120,000
8 0
4 years ago
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Instructions: Find the following information using the given image.
NNADVOKAT [17]

Answer:

Hypotenuse: 100

Segment Adjacent to the leg: 36

x=60

Step-by-step explanation:

I submitted and it was correct

6 0
3 years ago
(2n – 3)(5n+6)<br> How do I solve this ?
nalin [4]

Answer:

Step-by-step explanation:

(2n - 3)(5n + 6) = 2n*(5n + 6) -3*(5n +6)

=2n*5n + 2n*6 -3*5n + (-3)*6

=10n² + 12n - 15n - 18

= 10n² -3n - 18

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Pleaseee helppp with thissss asapppp
Natasha2012 [34]

As we know that the standard equation of circle is {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

{:\implies \quad \sf 9+16=r^{2}}

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

8 0
2 years ago
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