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Arturiano [62]
4 years ago
12

Construct a​ 95% confidence interval for the population​ mean, mu. Assume the population has a normal distribution. A sample of

25 randomly English majors has a mean test score of 81.5 with a standard deviation of 10.2. A. ​(77.29, 85.71) B. ​(66.35, 69.89) C. ​(56.12, 78.34) D. ​(87.12, 98.32)
Mathematics
1 answer:
blagie [28]4 years ago
3 0

Answer:

reeeeeeeeeeeee

Step-by-step explanation:

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aksik [14]
If two events are disjoint (i.e. mutually exclusive) they cannot both occur and so we can determine probabilties by simple addition:

P(AorB)=P(A)+P(B) 
P(AorB)=\frac{40}{61}+\frac{2}{61} 
P(AorB)=\frac{42}{61} 
P(AorB)\approx 68.8\% 

A more complete answer would use a joint probability table but that's difficult to type out/format correctly here. 
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Use the Two-Transversal Proportionality Corollary to find the value of x.
Artist 52 [7]
I hope this helps you




12/12+x=13/13+26



12/12+x=13/39



12/12+x=1/3



12+x=36


x=24
5 0
3 years ago
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GarryVolchara [31]
The answer is 1,936 Hope this helped
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Answer:true!!!

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