Answer:
a) 4160 V
b) 12 kW and 81 kVAR
c) 54 kW and 477 kVAR
Explanation:
1) The phase voltage is given as:

The complex power S is given as:


The line current I is given as:

The phase voltage at the sending end is:

The magnitude of the line voltage at the source end of the line (
b) The Total real and reactive power loss in the line is:

The real power loss is 12000 W = 12 kW
The reactive power loss is 81000 kVAR = 81 kVAR
c) The sending power is:

The Real power delivered by the supply = 54000 W = 54 kW
The Reactive power delivered by the supply = 477000 VAR = 477 kVAR
Answer:
Vf = specific volume of saturated liquid = 0.0217158 ft^3/lb
Vg = specific volume of saturated steam = 0.430129 ft^3/lb
Explanation:
Given data:
water temperature is given as 287-degree Celcius
we have to find Vf and Vg
Vf = specific volume of saturated liquid
Vg = specific volume of saturated steam
we know that from the saturated steam table we can find these value
therefore for temperature 287-degree Celcius
Vf = specific volume of saturated liquid = 0.0217158 ft^3/lb
Vg = specific volume of saturated steam = 0.430129 ft^3/lb