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RideAnS [48]
3 years ago
7

Technician A says that weld-through primer can be removed from the immediate weld area to improve weld quality. Technician B say

s that weld-through primer can be removed from adjacent areas to the weld site to improve penetration. Who is right
Engineering
1 answer:
lisabon 2012 [21]3 years ago
4 0

Answer:

83737373777473737373738388383838

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What’s the most important benefit of maintaining a neutral posture
olga55 [171]
Neutral posture is essential for optimal wellbeing and functioning of the body. Holding the weight of the body The most important function of a neutral posture is to maintain the body in an upright position, supporting the body against gravity
7 0
3 years ago
A rear wheel drive car of mass 1000 kg is accelerating with a constant acceleration without slipping from 0 to 60 m/s in 1 min.
tester [92]

Answer:

500 N

Explanation:

Given;

Mass of the car, M = 1000 kg

initial speed of the car, u = 0 m/s

Final speed of the car, v = 60 m/s

Time, t = 1 min = 60 s

Now,

Force, F is given as:

F = Ma

where,

a is the acceleration

From the Newton's equation of motion, we have

v = u + at

on substituting the values, we get

60 = 0 + a × 60

or

a = 1 m/s²

Thus,

Force = 1000 × 1 = 1000 N

now,

this force will be equal to the friction force provided by the rear wheels

let the friction force on a single rear wheel be 'f'

thus,

2f = 1000 N

or

f = 500 N

5 0
4 years ago
A 65% efficient turbine receives 2 m^3/s of water from a reservoir. The reservoir water surface is 45 m above the centerline of
laiz [17]

Answer:

P_{out} = 508.071 kW

Given:

efficiency of the turbine, \eta = 65% = 0.65

available gross head,  H_{G} = 45 m

head loss,  H_{loss} = 5 m

Discharge, Q =  2 m^{3}

Solution:

The nozzle is 100% (say)

Available power at the inlet of the turbine,  P_{inlet} is given by:

P_{inlet} = \rho Qg(H_{G} - H_{loss})                  (1)

where

\rho = density of water = 997 kg/m^{3}

acceleration due to gravity, g = 9.8 m^{2}

Using eqn (1):

P_{inlet} = 997\times 2\times 9.8(45 - 5) = 781.65 kW

Also, efficency, \eta is given by:

\eta = \frac{P_{out}}{P_{inlet}}

0.65 = \frac{P_{out}}{781.648\times 1000}

P_{out} = 0.65\times 781.648\times 1000 = 508071 W = 508.071 kW

P_{out} = 508.071 kW

3 0
3 years ago
Software piracy occurs when
mario62 [17]

Answer:

Someone steals software

3 0
3 years ago
The ignition temperature of 87-octane gasoline vapor is about 430 ∘C and, assuming that the working gas is diatomic and enters t
Flura [38]

Answer:

I have solved the problem below. I hope it will let you clear the concept.

For any inquiries ask me in the comments.

Explanation:

6 0
4 years ago
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