Answer:
Fcte10 < Fcte01 = Fcte0 < Fctm11 < Fcte21 = Fctm21 < Fcte12 = Fctm12 < Fcte22
Explanation:
Assuming a = 2b
Attached below is the required steps to the solution
The cutoff frequencies for the first ten modes of a rectangular waveguide listed in ascending order is :
Fcte10 < Fcte01 = Fcte0 < Fctm11 < Fcte21 = Fctm21 < Fcte12 = Fctm12 < Fcte22
Answer:
True
Explanation:
To carry out a research in order to that it should yield the desirable result, a researcher must be very clear about his objective for the research.
The researcher must be very much clear about all the do's and don'ts and all the where, why, what sort of thing, i.e., the researcher must be clear about his/her intentions of carrying out the research, and what research is being carried out by him/her.
The one doing the research must be clear about the implications of the research.
Unless all these things are not clear at the researcher's end the research will not give the desired results.
A good visual lead is 20-30 seconds from the front of the vehicle, focusing in the center of the path of travel. Searching 20 to 30 seconds ahead, gives you time to assess within the next ..12-15 seconds, actions you may need to take to control an approaching risk.
Discussion:
Keeping eye focus centered in a path of travel at an interval of 20 to 30 seconds away from the vehicle is critical to gaining enough info. as possible in the driving scene. Good targeting sets up good sight lines for referencing and good peripheral fields for observing changes.
- It is important to look ahead 12-15 seconds into your target area as one drives. Compromise. space by giving as much space to the greater of two hazards.
Read more on driving visual leads:
brainly.com/question/7067386
Answer:
13177.34 J
Explanation:
Work done = force × distance
work done by the engine = kinetic energy + potential energy + work done friction
kinetic energy due to the car's speed = 1/2mv² = 4468.5 J
potential energy due to the height = mgh = 993 kg × 9.8 m/s² × 0.6 m = 5838.84 J
work done by friction = 2870 J
work done by engine = 5838.84 J + 2870 J + 4468.5 J = 13177.34 J