Answer:
In skating, one skate pushes and the other skate glides--there is very little friction to slow you down. Speed skater Hiroyasu Shimizu of Japan can travel 500 meters in just 35.39 seconds, an average speed of 14.13 meters per second or 31.6 miles per hour.
Step-by-step explanation:
Answer:
A. Between 3.0 and 3.5 and between 4.0 and 4.5
Step-by-step explanation:
The zeroes of a function occur whenever a value of x returns zero. To predict where the zeroes lie, determine the interval(s) where the function crosses the x-axis. This occurs when either goes from a negative value to a positive value or vice versa.
From and , the y-values go from 4.0 (positive) to -0.2 (negative), respectively. Therefore, there must be a zero in this interval.
From and , the y-values go from -0.8 (negative) to 0.1 (positive), respectively. Therefore, there must also be a zero in this interval.
Thus, the zeros of this function occur between 3.0 and 3.5 and between 4.0 and 4.5, leading to answer choice A.
X + 27 = 14
27-14 = 13
-13 + 24 = 14
the answer is -13
Answer: It is worth it.
Step-by-step explanation:
If a customer sends 101 - 200 texts in a month, they get charged 8 cents per text.
If they send 201 - 300, they get charged 6 cents per month.
If you have sent 200 texts, your charge for the month will therefore be:
= 200 * 8
= $16.00
If you send the 201th text, you will be charged 6 cents per text. Total charge would be:
= 201 * 6
= $12.06
<em>If you send 1 more text, it will be worth it because you will save:</em>
<em>= 16 - 12.06</em>
<em>= $3.94</em>
Given:
h(t) = -16t² + 90t + 50
g(t) = 28 + 48.8t
h(1) = -16(1²) + 90(1) + 50 = 124
h(2) = -16(2²) + 90(2) + 50 = -64 + 180 + 50 = 166
h(3) = -16(3²) + 90(3) + 50 = -144 + 270 + 50 = 176
h(4) = -16(4²) + 90(4) + 50 = -256 + 360 + 50 = 154
g(1) = 28 + 48.8(1) = 76.80
g(2) = 28 + 48.8(2) = 125.60
g(3) = 28 + 48.8(3) = 174.40
g(4) = 28 + 48.8(4) = 223.20
Between 3 seconds is the answer... though it is not exactly equal but they are nearer in value compared to other number of seconds.