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alexdok [17]
3 years ago
12

Suppose f and g are continuous functions such that g(4)=6 and lim x->4 [3f(x)+f(x)g(x)] = 45. Find f(4). ... (How do I begin

solving this problem? Step by step assist please)
Mathematics
1 answer:
Citrus2011 [14]3 years ago
5 0

Answer:

The value of f(4) is 5. We can write f(4) = 5.

Step-by-step explanation:

Since it is given that

\lim_{x\rightarrow 4}[3f(x)+f(x)g(x)]=45

This is only possible if both the functions f(x) and g(x) are continuous at x = 4.

Now since the functions are continuous at x = 4 they need to be defined at the said value in accordance with the definition of continuous function.

Thus  to obtain the limit we just put x = 4 in left hand side of the given relation thus getting

[3f(4)+f(4)g(4)]=45..........(i)

Now applying the given value of g(4) in equation 'i' we get

3f(4)+6f(4)=45\\\\9f(4)=45\\\\\therefore f(4)=\frac{45}{9}=5

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Answer:

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Step-by-step explanation:

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Find the 12th term of the geometric sequence 5, -25, 125, ...5,−25,125,...
katovenus [111]

Answer:

  • a_{12}=-244140625

Step-by-step explanation:

Considering the geometric sequence

5,-25,\:125,\:...

a_1=5

As the common ratio 'r' between consecutive terms is constant.

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}

r=\frac{-25}{5}=-5

r=\frac{125}{-25}=-5

The general term of a geometric sequence is given by the formula:  

a_n=a_1\cdot \:r^{n-1}

where a_1 is the initial term and r the common ratio.

Putting n = 12 , r = -5 and a_1=5 in the general term of a geometric sequence to determine the 12th term of the sequence.

a_n=a_1\cdot \:r^{n-1}

a_n=5\left(-5\right)^{n-1}

a_{12}=5\left(-5\right)^{12-1}

      =5\left(-5^{11}\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

       =-5\cdot \:5^{11}

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

        =-5^{1+11}     ∵ 5\cdot \:5^{11}=\:5^{1+11}

        =-244140625

Therefore,

  • a_{12}=-244140625
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3 years ago
A cube with a side of 1m was sawn into cubes with a side of 1 cm and then laid in a row (in a straight line). What was the lengt
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Answer:

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Step-by-step explanation:

volume of cube = s^3

1 m = 100 cm

volume = s^3 = (1 m)^3 = (100 cm)^3 = 1,000,000 cm^3

Since 1 m^3 = 1,000,000 cm^3, when you lay down the 1-cm cubes in a straight line with the edges touching, the line is 1,000,000 cm long.

1,000,000 cm = 10,000 m = 10 km

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Answer:

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Step-by-step explanation:

(4x5) + ((4x3)/2)  + ((4x2)/2) = 20 in sq.

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What is the scale factor very urgent
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Answer:

The scale factor of the triangle if of 3.

Step-by-step explanation:

All you have to do is use figure A and either multiply or divide by a number to get figure B. In this case, the straight vertical side of Figure A is 6 units, and the straight vertical side of Figure B is 2. So 6 divided by 2 is 3. That means that the scale factor of the triangle is of 3. The triangle contracted it's size by 3.  

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