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alexdok [17]
4 years ago
12

Suppose f and g are continuous functions such that g(4)=6 and lim x->4 [3f(x)+f(x)g(x)] = 45. Find f(4). ... (How do I begin

solving this problem? Step by step assist please)
Mathematics
1 answer:
Citrus2011 [14]4 years ago
5 0

Answer:

The value of f(4) is 5. We can write f(4) = 5.

Step-by-step explanation:

Since it is given that

\lim_{x\rightarrow 4}[3f(x)+f(x)g(x)]=45

This is only possible if both the functions f(x) and g(x) are continuous at x = 4.

Now since the functions are continuous at x = 4 they need to be defined at the said value in accordance with the definition of continuous function.

Thus  to obtain the limit we just put x = 4 in left hand side of the given relation thus getting

[3f(4)+f(4)g(4)]=45..........(i)

Now applying the given value of g(4) in equation 'i' we get

3f(4)+6f(4)=45\\\\9f(4)=45\\\\\therefore f(4)=\frac{45}{9}=5

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Answer:

B. \sqrt{65}

Step-by-step explanation:

Find the missing length by subtracting 5^2-3^2 to get 4^2.

Then do 4^2+7^2 to get 65

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3 years ago
Ok so I wanted to make sure my math was correct <br> Is 274.43 - 20.46 - 25.89 = 228.08
romanna [79]
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5 0
3 years ago
Read 2 more answers
Joe can cut and split a cord of firewood in 3 fewer hours than Dwight can. When they work​ together, it takes them 2 hours. How
aalyn [17]

Answer:

Dwight will take 6 hours to finish the job alone and Joe will take 3 hours to finish the job alone.

Step-by-step explanation:

Let us assume the time taken by Dwight to split a cord of firewood  = K hrs

So, the per hour rate of Dwight  = (\frac{1}{K})

As, Joe uses 3 LESS hours then Dwight.

So, the time taken by Joe to split a cord of firewood  = (K- 3) hrs

So, the per hour rate of Joe  = (\frac{1}{K-3})

Now, when both of them wok together, it takes them 2 hours.

So, the per hour rate of BOTH of them  = (\frac{1}{2})

⇒ Per hour rate of ( Dwight  + Joe)  =(\frac{1}{2} )

\implies (\frac{1}{K}) +  (\frac{1}{K-3}) = (\frac{1}{2})

Now, solving for the value of K , we get:

(\frac{1}{K}) +  (\frac{1}{K-3}) = (\frac{1}{2})\\\implies  \frac{(K-3) + K}{K (K-3)}  = (\frac{1}{2})\\\implies 2(2K -3) = K^2 - 3K\\\implies k^2 - 3K -4K +6 = 0\\\implies K^2 - 7K  + 6=  0\\\implies K^2 - 6K - K  + 6=  0\\\implies K(K-6) -1(K - 6)=  0\\\implies (K-6)(K-1) = 0

Implies either K = 6 Or K = 1

But if K = 1, (K-3)  = 1- 3  = -2 hours would be A CONTRADICTION.

⇒ K  = 6 hours

Hence, Dwight will take 6 hours to finish the job alone and Joe will take (k-3) = (6-3) = 3 hours to finish the job alone.

8 0
3 years ago
What is the length of side ab in equilateral triangle abc if the length of altitude ad to side bc is 12?
I am Lyosha [343]
\lim_{n \to \infty} a_n
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4 years ago
They make a base of 50 gallons (20%). They make a “heavy batch of 150 gallons (80%) They mix them both. What is the percent of
SSSSS [86.1K]
Answer #1: x= 250

50 = x times 20/100

X= 100 times 50/ 20

X=250

Answer #2: same explanation but the answer is X= 120

If your talking about merging the percentage of the answer, I can’t help you with that
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3 years ago
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