1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexdok [17]
3 years ago
12

Suppose f and g are continuous functions such that g(4)=6 and lim x->4 [3f(x)+f(x)g(x)] = 45. Find f(4). ... (How do I begin

solving this problem? Step by step assist please)
Mathematics
1 answer:
Citrus2011 [14]3 years ago
5 0

Answer:

The value of f(4) is 5. We can write f(4) = 5.

Step-by-step explanation:

Since it is given that

\lim_{x\rightarrow 4}[3f(x)+f(x)g(x)]=45

This is only possible if both the functions f(x) and g(x) are continuous at x = 4.

Now since the functions are continuous at x = 4 they need to be defined at the said value in accordance with the definition of continuous function.

Thus  to obtain the limit we just put x = 4 in left hand side of the given relation thus getting

[3f(4)+f(4)g(4)]=45..........(i)

Now applying the given value of g(4) in equation 'i' we get

3f(4)+6f(4)=45\\\\9f(4)=45\\\\\therefore f(4)=\frac{45}{9}=5

You might be interested in
-5x+7+2x-13<9 Please Explain
olganol [36]
Ok the answer is -5 less than 9 which is true lol


Anyways here’s how I got the answer

-5+7+2x-13 less than 9

Combine like terms in this case it’s -5 and 2, and the other is 7 and -13

-5+2= -3
7-13= -6

Ok now that that’s done here’s the next step

-3x-6 less than 9 solve it


-3x-6 < 9
+6< +6

-3x < 15



Now from there you divide then so
-3x/3 cancels out, and 15/-3 = -5
X=-5

And so -5<9 :) hope this helped!! I will also include a picture of my work (please exult messiness lol)

8 0
3 years ago
Need help nowwww!!! With 1 threw 8
JulijaS [17]

1. B

2. B

3.C

4.B

5.B

6.A

6 0
3 years ago
Find the value of x is y=0
Drupady [299]

Answer:

01= x

Step-by-step explanatiothis is the answer

7 0
3 years ago
At a grocery store I bought a bag of 7 apples. Some apples are red and some apples are green. How many combination of 7 apples c
nordsb [41]
6, I guess. 1 red and 6 green, 2 red and 5 green. 3 red and 4 green, 2 green and 5 red, 1 green and 6 red, 3 green and 4 red, 
6 0
3 years ago
HELP!!!!!!!!!!!!! Please
Arturiano [62]

Probability helps us to know the chances of an event occurring. There are six possible outcomes.

<h3>What is Probability?</h3>

Probability helps us to know the chances of an event occurring.

\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}

A.) The outcomes that are possible from the first spinner is 1, 2, and 3, while the outcomes possible from the second spinner are 2, Red and blue.

All the possible outcomes from this two spinner are,

(B,1), (B,2), (B,3), (R,1), (R,2), and (R,3).

Hence, there are six possible outcomes.

B.) The letters that can be used are A and B. The numbers that can be used are 1, 2, 3, and 4.

All the possible out comes are,

(B,1), (B,2), (B,3)(B,4), (A,1), (A,2), (A,3), and (A,4).

Learn more about Probability:

brainly.com/question/795909

#SPJ1

3 0
2 years ago
Other questions:
  • Find the circumference of a circle with a radius of 10 inches
    6·2 answers
  • Which set of angles can form a triangle?
    11·1 answer
  • Really need help/offering brainiest answer-6=x/8+4 <br><br> 1.8<br> -16<br> 16<br> -80
    6·2 answers
  • This is really hard please help
    7·2 answers
  • The basic metric unit of capacity is the liter. True False
    12·2 answers
  • Hallar un numero,cuyo duplo aumentado en 5 es a su cuadruplo disminuido en 5 como 5 es a 7
    9·1 answer
  • Which of the following is the equation of a line in slope-intercept form for a
    12·1 answer
  • 2/5 of a kiddy pool was filled with water. After pouring out 5/7
    11·1 answer
  • Explain why the following is incorrect x3v4=x7
    14·1 answer
  • Please help I can't figure out the mode
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!