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2 years ago

84,000 of food for 80 soldiers for 60 days How long would the food last 20 more soldiers joined

Mathematics

1 answer:

larisa [96]2 years ago

5 0

Answer:

If 20 more soldiers join it would last 48 days

Step-by-step explanation:

if 80 soldiers need 84000 food for 60 days it means that in 60 days one soldier eats 84000/80= 1050 each

then 1050/60=17.5 meaning they need 17.5 food a day each,

adding 20 soldiers means 80+20= 100 soldiers

100*17.5=1750 food is eaten every day

84000/1750= 48 which means that 100 soldiers will eat 84000 in 48 days

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When building the Channel, the English and French each started drilling on opposite sides of the English Channel. The two sectio

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Suppose the English could drill the Channel in 6.2 years, then they drill with speed $\dfrac{L}{6.2}$ km per year, where L is the length of the English Channel. If the French could drill in 5.8 years, then their speed of drillling is $\dfrac{L}{5.8}$ km per year.

Together their speed will be

$\dfrac{L}{6.2} +\dfrac{L}{5.8} =\dfrac{5.8L+6.2L}{6.2\cdot 5.8}=\dfrac{12L}{35.96}=\dfrac{3L}{8.99}$ .

If they drill together, they will spend

$\dfrac{L}{\frac{3L}{8.99}} =\dfrac{8.99}{3}=2.9966666....\approx 3$ years.

Answer: it would have taken nearly 3 years.

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2 years ago

Need help solving for relative frequency please!

Sunny_sXe [5.5K]

Answer:

Kindly check explanation

Step-by-step explanation:

Given :

Relative frequency = frequency / total frequency

Total frequency = 389+335+975+351+72 = 2122

Response ________ Frequency __ R/ frequency

Never ____________ 389 _ 389/2122 = 0.180

Rarely ____________ 335 _ 335/2122 = 0.158

Sometimes _________975 _975/2122 = 0.459

Most of the time _____ 351 _ 351/2122 = 0.165

Always ____________ 72 __ 72/2122 = 0.034

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2 years ago

You are preparing for a trip to Canada. At the time of your trip, each U.S. Dollar is worth 1.293 Canadian dollars and each Cana

madreJ [45]

Answer:

193.95 Canadian dollars

Step-by-step explanation:

Given: Each U.S. Dollar is worth 1.293 Canadian dollars and each Canadian dollar is worth 0.773 U.S. Dollar.

To find: Value of 150 U.S. dollars in terms of Canadian dollars

Value of 1 U.S. dollar = 1.293 Canadian dollars

To find 150 U.S. dollars in terms of Canadian dollars, multiply 150 by 1.293

Value of 150 U.S. dollars in terms of Canadian dollars = 150 × 1.293 = 193.95 Canadian dollars

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2 years ago

Let us have four distinct collinear points $a,$ $b,$ $c,$ and $d$ on the cartesian plane. the point $c$ is such that $\dfrac{ab}

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Start with a line segment connecting two points, A and B. $\dfrac{DA}{BA}=3$ means DA is 3 times longer than BA. Clearly, D cannot fall between A and B because that would mean DA is shorter than BA. So there are two possible locations where D can be placed on the line relative to A and B.

But with $\dfrac{DB}{BA}=2$ , or the fact that DB is 2 times longer than BA, we can rule out one of these positions; referring to the attachment, if we place D to the left of A, then DB would be 4 times longer than BA.

Finally, $\dfrac{AB}{CB}=\dfrac12$ , so that CB is 2 times longer than AB. Again we have two possible locations for point C (it cannot fall between A and B), but one of them forces C to occupy the same point as D. However, A, B, C, D are distinct, so C must fall to the left of A.

Now let $d$ be the length of AB. Then the length of CD in terms of $d$ is $4d$ . We have the coordinates of C and D, and the distance between them is $\sqrt{(4-0)^2+(0-4)^2}=4\sqrt2$ . So

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$\dfrac{0-4}{4-0}=-1$

and so the equation of the line through these points is

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So the coordinates of A are $(x,y)=(x,4-x)$ . The distance between C and A is $d=\sqrt2$ , so we have

$\sqrt{(x-0)^2+(4-x-4)^2}=\sqrt{2x^2}=|x|\sqrt2=\sqrt2\implies|x|=1$

Since A falls to the right of C (in the $x,y$ plane, not just in the sketch), we know to take the positive value $x=1$ . Then the $y$ coordinate is $y=4-1=3$ .