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Len [333]
4 years ago
4

In the seventeenth century, Robert Hooke conducted many experiments with springs. In all the data he recorded, he found that the

force needed to push down on a spring or stretch it out from its usual resting point was equal to the spring’s stiffness multiplied by the distance it is pushed or pulled from its resting point. He wrote the equation F = kX, in which F is the force, k is the spring’s stiffness, and X is the distance the end of the spring moves from its usual resting point when no push or pull is applied. The equation is still used today. Which best describes Hooke’s equation? It is a law, because it explains why a force must be applied to push or pull a spring. It is a law, because it states how force relates to a spring but does not explain why. It is a theory, because it explains why a force must be applied to push or pull a spring. It is a theory, because it states how force relates to a spring but does not explain why.
Physics
2 answers:
BlackZzzverrR [31]4 years ago
8 0

Answer:

It is a law, because it states how force relates to a spring but does not explain why.

Explanation:

It is also known as Hooke's law. by the help of this law we can find the relation between force exerted due to spring and the displacement of the one end of spring from its natural length.

This is verified experimentally that how the length of the spring will change and that requires how much force to balance the force due to spring.

So in this experiment we can observe that more force is required to pull or push the spring by more distance.

So here we will say that any description which is verified experimentally but not theoretically then it must be a law.

so correct answer will be

It is a law, because it states how force relates to a spring but does not explain why.

k0ka [10]4 years ago
3 0
It is a law, because it states how force relates to a spring but does not explain why.The explanation of the relationship between load and extension is not in Hooke's Law.<span>
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JulijaS [17]

The coefficient of kinetic friction between the baserunner and the ground is 0.51.

<h3>Coefficient of kinetic friction </h3>

The coefficient of kinetic friction between the base runner and the ground is calculated as follows;

μ = a/g

where;

  • a is acceleration
  • g is gravity

v² = u² + 2as

a = (v² - u²)/(2s)

a = (8.451² - 2.322²)/(2 x 6.596)

a = 5 m/s²

μ = 5/9.8

μ = 0.51

Thus, the coefficient of kinetic friction between the baserunner and the ground is 0.51.

Learn more about coefficient of friction here: brainly.com/question/14121363

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7 0
2 years ago
Beatrice and the Elevator Beatrice, a middle school student, is visiting a very tall office building and notices that she feels
ahrayia [7]

Explanation:

The question is not complete, here is the complete question

<em>"Beatrice and the Elevator Beatrice, a middle school student, is visiting a very tall office building and notices that she feels heavier when the elevator car is traveling up and lighter when the elevator car is traveling down. After making these observations, Beatrice comes back to the building and stands on a bathroom scale that measures her weight as she travels up and down in the elevator.</em>

<em>1. . What question is Beatrice trying to answer?</em>

<em>2. What is one variable Beatrice could change in her investigation? What might she figure out if this </em>

<em> variable was changed"</em>

1. Beatrice is trying to observe the influence of the elevator movement on her weight, Hence the question is<em> "will the elevator  movement cause her weight to change"</em>

therefore moving upward the reading on the scale will increase

Reading=mg+ma

downward

Reading will reduce

Reading=mg-ma

2. The independent variable is the acceleration due to gravity g=9.81m/s^2

while the dependent variables are

    i. The elevators acceleration

    ii. Beatrice's mass

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Describe possible instrumental error
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Look on chegg.com/instrumentalerrors for answer
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3 years ago
A sled is at rest at the top of a slope 2 m high. The sled has a mass of 45 kg. What is the sled's potential energy?
kap26 [50]

Answer:

PE = 882 J

Explanation:

Through the International System we know that the gravity of the earth is 9.8 m/s², so...

Data:

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  • g = 9.8 m/s²
  • h = 2 m
  • PE = ?

Formula:

  • \boxed{\bold{PE=m*g*h}}

Replace and solve:

  • \boxed{\bold{PE=45\ kg*\ 9.8\frac{m}{s^{2}}*2\ m}}
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The potential energy of the sled is <u>882 Joules</u>.

Greetings.

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Answer:

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Explanation:

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