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Inga [223]
3 years ago
11

Diagnostic ultrasound of frequency 3.45 MHz is used to examine tumors in soft tissue.

Physics
1 answer:
Mekhanik [1.2K]3 years ago
6 0

Answer:

4.35×10⁻⁴ m

Explanation:

(a)

From wave,

v = λf...................... Equation 1

Where v = speed of sound in air, λ = wavelength of sound, f = frequency of sound.

Make λ the subject of formula in  equation 1

λ = v/f................. Equation 2

Given: v = 343, f = 3.45 MHz = 3.45×10⁶ Hz

Substitute into equation 2

λ = 343/(3.45×10⁶)

λ = 99.42×10⁻⁶ m

λ = 9.942×10⁻⁵ m

(b)

using,

v' = λ'f............... Equation 3

Where v' = speed of sound in tissue, λ' = wavelength of sound in tissue.

make λ' the subject of the equation

λ' = v'/f......................Equation 4

Given: v' = 1500 m/s, f = 3.45 MHz = 3.45×10⁶ Hz

Substitute into equation 4

λ' = 1500/(3.45×10⁶)

λ' = 434.783×10⁻⁶

λ' ≈ 4.35×10⁻⁴ m.

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Jill applies a force of 250 N to a machine. The machine applies a force of 25 N to an object. What is the mechanical advantage o
Vinvika [58]

Mechanical advantage is defined as the ratio of output load to the input load. The mechanical advantage of the machine will be 0.1.

<h3>What is mechanical advantage?</h3>

Mechanical advantage is a measure of the ratio of output force to input force in a system,

It is used to obtain the efficiency of forces in levers and pulleys. It is an effective way of amplifying the force in simple machines like levers.

The theoretical mechanical advantage is defined as the ratio of the force responsible for the useful work in the system to the applied force.

Given

applied force = 250 N

Output force = 25

Mechanical advantage = work output / work input

\rm{Mechanical advantage}=\frac{F_O}{F_I}

\rm{Mechanical advantage}=\frac{25}{250}

\rm{Mechanical advantage}=0.1

Hence the mechanical advantage of the machine will be 0.1

To learn more about the mechanical advantage refer to the link;

brainly.com/question/7638820

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2 years ago
A simple harmonic oscillator completes 1550 cycles in 30 min. (a) Calculate the period. s (b) Calculate the frequency of the mot
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Answer:

(a) 1.16 s

(b)0.861 Hz

Explanation:

(a) Period : The period of a simple harmonic motion is the time in seconds, required for a object undergoing oscillation to complete one cycle.

From the question,

If 1550 cycles is completed in (30×60) seconds,

1 cycle is completed in x seconds

x = 30×60/1550

x = 1.16 s

Hence the period is 1.16 seconds.

(b) Frequency : This can be defined as the number of cycles that is completed in one seconds, by an oscillating body. The S.I unit of frequency is Hertz (Hz).

Mathematically, Frequency is given as

F = 1/T ........................... Equation 1

Where F = frequency, T = period.

Given: T = 1.16 s.

Substitute into equation 1

F = 1/1.16

F = 0.862 Hz

Hence thee frequency = 0.862 Hz

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