Answer:
v₀ = 3.77 [m/s]
Explanation:
This problem can be solved in a simple way by means of the following equation of kinematics.
where:
y - yo = 0.441 [m]
Vo = initial velocity [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time = 0.625 [s]
![0.441 = v_{o}*(0.625)-\frac{1}{2} *9.81*(0.625)^{2} \\2.357 = v_{o}*0.625\\v_{o}=3.77[m/s]](https://tex.z-dn.net/?f=0.441%20%3D%20v_%7Bo%7D%2A%280.625%29-%5Cfrac%7B1%7D%7B2%7D%20%2A9.81%2A%280.625%29%5E%7B2%7D%20%5C%5C2.357%20%3D%20v_%7Bo%7D%2A0.625%5C%5Cv_%7Bo%7D%3D3.77%5Bm%2Fs%5D)
Note: The sign of the acceleration is negative since the movement of the basketball player is against of the gravity acceleration.
Answer:
15 V
Explanation:
From the question,
For series connection: (i) Both resistor have a common current flowing through the (ii) The combined resistance = R1+R2
Rt = R1+R2.................. Equation 1
Given: R1 = 5 ohms, R2 = 7.5 ohms.
Rt = 5+7.5 = 12.5 ohms.
Applying Ohm's law,
V = IRt................... Equation 2
Where V = Voltage, I = current.
make I The subject of the equation
I = V/Rt.............. Equation 3
Given: V = 25 V, Rt = 12.5 ohms.
Substitute into equation 3
I = 25/12.5
I = 2 A.
Now,
Voltage drop across the 7.5 ohms resistor = R2×I
Voltage drop across the 7.5 ohms resistor = 7.5×2
Voltage drop across the 7.5 ohms resistor = 15 V
Answer:
Explanation:
Magnetic field B = 6 X 10⁻⁵ T.
Width of car = L (Let )
Velocity of car v = 100 km/h
= 27.78 m /s
induced emf across the body ( width ) of the car
= BLv
= 6 X 10⁻⁵ L X 27.78
166.68 X 10⁻⁵ L
Induced electric field across the width
= emf induced / L
E = 166.68 X 10⁻⁵ N/C
We suppose breadth of a typical car = 1.5 m
potential difference induced
= 166.68 x 1.5 x 10⁻⁵
250 x 10⁻⁵ V
= 2.5 milli volt.
The side of the car which is positively charged depends on the direction in which car is moving , whether it is moving towards the north or south.
Missing question:
"Determine (a) the astronaut’s orbital speed v and (b) the period of the orbit"
Solution
part a) The center of the orbit of the third astronaut is located at the center of the moon. This means that the radius of the orbit is the sum of the Moon's radius r0 and the altitude (
) of the orbit:
This is a circular motion, where the centripetal acceleration is equal to the gravitational acceleration g at this altitude. The problem says that at this altitude,
. So we can write
where
is the centripetal acceleration and v is the speed of the astronaut. Re-arranging it we can find v:
part b) The orbit has a circumference of
, and the astronaut is covering it at a speed equal to v. Therefore, the period of the orbit is
So, the period of the orbit is 2.45 hours.
