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Novay_Z [31]
2 years ago
6

WILL MARK BRAINLIEST

Physics
1 answer:
Elanso [62]2 years ago
7 0

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An alternating source drives a series RLC circuit with an emf amplitude of 6.34 V, at a phase angle of +33.3°. When the potentia
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Answer:

V_{L}  =- 8.78v

Explanation:

E^{2} _{m}= V^{2} _{R} + (V_{L} -V _{C} )^{2}

OR  V_{L} = V_{c}  + \sqrt{E^{2}{m}  - V^{2} {R}  }

where VR = E{m}cosФ

V_{L} = V_{c}  + \sqrt{E^{2}_{m} - E^{2}_{m} cos^{2}   }Ф

V_{L} = V_{c} + {E_{m} \sqrt{1 - cos^{2} }  }Ф

V_{L} = V_{c} + E_{m}sinФ

substituting the given values

V_{L}  = 5.33 + 6.34 x sin33°

V_{L} = -8.78v

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