WILL MARK BRAINLIEST

1. Meiosis produces daughter cells that are

Marina86 [1]

Answer:

1. A Haploid

2. A. Somatic Cell production

3. B. Gametic cell production

4. C. Mitosis produces identical cells to parent cells.

5. B 4:0

6. C Both parent bees are heterozygous Ll

7. D DNA is made up of chromosomes

8. B Each hypothesis was tested and DNA supported the data better

9. D There may be an increase in pest populations that are resistant to control measures.

10. A They are proven to cause cancer.

11. B a form of a gene

Explanation:

Answer was too long, so is attached in a word document

Download docx

5 0

4 years ago

What is the work done by a car's braking system when it slows the 1500-kg car from an initial speed of 96 km/h down to 56 km/h i

kondor19780726 [428]

Answer:

-352.275KJ

Explanation:

We are given that

Mass of car=1500kg

Initial speed of car =u=96 km/h= $96\times \frac{5}{18}=26.67m/s$

1km/h= $\frac{5}{18}m/s$

Final speed of car=v=56km/h= $56\times \frac{5}{18}=15.56m/s$

Distance traveled by car=s=55m

We have to find the work done by the car's braking system.

Using third equation of motion

$v^2-u^2=2as$

$(15.56)^2-(26.67)^2=2a(55)$

$-469.18=110a$

$a=\frac{-469.18}{110}=-4.27m/s^2$

Where negative sign indicates that velocity of car decreases.

Work done by a car's barking system= $w=F\times s=ma\times s$

Work done by a car's barking system= $1500\times -4.27\times 55=352275J$

Work done by a car's barking system= $-\frac{352275}{1000}=-352.275KJ$

1KJ=1000J

Where negative sign indicates that work done in opposite direction of motion.

7 0

4 years ago

Read 2 more answers

A glass slab of density 2500kg/m3 measures 20cmx10cmx50cm what is maximum pressure

Vilka [71]

Answer:

A =150

I think it will help you bro

8 0

2 years ago

A small block of mass 1.57 kg rests on the left edge of a block of length 3.45 m and mass 7.04 kg. the coefficient of kinetic fr

MariettaO [177]

...............................................................

3 0

3 years ago

(a) A 1.00-μF capacitor is connected to a 15.0-V battery. How much energy is stored in the capacitor? ________ μJ (b) Had the ca

gulaghasi [49]

Answer:

(a) $E_{ c} = 112.5 \mu J$

(b) $E'_{ c} = 18 \mu J$

Solution:

According to the question:

Capacitance, C = $1.00\mu F = 1.00\times 10^{- 6} F$

Voltage of the battery, $V_{b} = 15.0 V$

(a)The Energy stored in the Capacitor is given by:

$E_{c} = \frac{1}{2}CV_{b}^{2}$

$E_{c} = \frac{1}{2}\times 1.00\times 10^{- 6}\times 15.0^{2}$

$E_{ c} = 112.5 \mu J$

(b) When the voltage of the battery is 6.00 V, the the energy stored in the capacitor is given by:

$E'_{c} = \frac{1}{2}CV'_{b}^{2}$

$E'_{c} = \frac{1}{2}\times 1.00\times 10^{- 6}\times 6.0^{2}$

$E'_{ c} = 18 \mu J$

6 0

4 years ago