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iVinArrow [24]
3 years ago
14

In a car engine, what type of energy is released at a high level, leading to inefficiency?

Physics
1 answer:
spin [16.1K]3 years ago
7 0
Thermal energy is the answer
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A machine produces 4,000 J of work in 5 seconds. how much power does the machine produce.
ad-work [718]

Explanation:

Power is defined as the work done per unit time or

P = \dfrac{\Delta W}{\Delta t}

\;\;\;\;= \dfrac{4000\:\text{J}}{5\:\text{s}} = 800\:\text{Watts}

5 0
2 years ago
A 100 kg boat is floating in water. half of the boat is submerged under water. what is the weight of the boat?
Alex17521 [72]
W=MG
w is weight 
m is mass
g is gravity 
W=(100 kg)(9.8 m/s)
W= 980 N
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7 0
3 years ago
If a source of sound waves is rapidly approaching a person, the sound heard by the person appears to have
velikii [3]

Correct answer choice is:

D. A frequency higher than the original frequency.

Explanation:

This is a true case of Doppler's effect. The Doppler effect can be defined as the effect originated by a traveling source of waves in which there is a visible higher variation in pulse for observers towards what the source is progressing and a visible descending shift in rate for observers from what the source is dropping.

8 0
3 years ago
Read 2 more answers
A 3.91 kg cart is moving at 5.7 m/s when it collides with a 4 kg cart which was at rest. They collide and stick together.
Nesterboy [21]

Answer:

<em>The velocity after the collision is 2.82 m/s</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is  

P=mv.  

If we have a system of two bodies, then the total momentum is the sum of the individual momentums:

P=m_1v_1+m_2v_2

If a collision occurs and the velocities change to v', the final momentum is:

P'=m_1v'_1+m_2v'_2

Since the total momentum is conserved, then:

P = P'

Or, equivalently:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

If both masses stick together after the collision at a common speed v', then:

m_1v_1+m_2v_2=(m_1+m_2)v'

The common velocity after this situation is:

\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}

There is an m1=3.91 kg car moving at v1=5.7 m/s that collides with an m2=4 kg cart that was at rest v2=0.

After the collision, both cars stick together. Let's compute the common speed after that:

\displaystyle v'=\frac{3.91*5.7+4*0}{3.91+4}

\displaystyle v'=\frac{22.287}{7.91}

\boxed{v' = 2.82\ m/s}

The velocity after the collision is 2.82 m/s

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3 years ago
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About what  elemental trip through europe
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